The answer you're looking for is 8
Answer:
The correct option is: AgNO₃(aq) + KCl(aq) = AgCl(s) + KNO₃(aq)
Explanation:
Precipitation reaction is a chemical reaction that involves reaction between <em>two soluble salts to give an insoluble salt.</em> This <u>insoluble salt exists as a solid</u> and settles down.
Therefore, the solid formed in a precipitation reaction is known as the precipitate.
As the solid silver nitrate (AgNO₃) and solid potassium chloride (KCl) are <u>soluble in water</u>, therefore, their aqueous solutions are represented as AgNO₃(aq) and KCl(aq), respectively.
The precipitation reaction of AgNO₃(aq) and KCl(aq) gives an <u>insoluble salt, silver chloride (AgCl) and a soluble salt, potassium nitrate (KNO₃).</u>
The insoluble salt, <u>AgCl is called the precipitate</u> and is represented as AgCl(s). Whereas, the <u>soluble salt</u>, KNO₃ is represented as KNO₃ (aq).
<u>Therefore, the chemical equation for this precipitation reaction is:</u>
AgNO₃(aq) + KCl(aq) → AgCl(s) + KNO₃(aq)
Answer: all other conditions equal, the rate evaporation of a contained liquid will be slower than the rate of evaporation of an uncontained liquid.
Justification:
1) The rate of evaporation increases as the surface area of the liquid (relative to the whole content) increases. This is, the greater the surface is the faster the evaporation.
2) That is so because the higher the surface of the liquid the more the number of particles in the liquid that are in contact with the surrounding air and so the more the particles will escape from the liquid to the air (which is what evaporation is).
3) A liquid contained will take the form of the container, so part of the liquid wil remain below the surface, while an uncontained liquid will spread all over the surface and so pratically all the liquid is in contact witht the air surrounding it.
The question is confusing and all the answers are not there but it is B C and D
Answer:
520 kg
Explanation:
Let's consider the combustion of isooctane.
C₈H₁₈(l) + 12.5 O₂(g) → 8 CO₂(g) + 9 H₂O(l)
We can establish the following relations:
- 1 mL of C₈H₁₈ has a mass of 0.690 g (ρ = 0.690 g/mL).
- The molar mass of C₈H₁₈ is 114.22 g/mol.
- The molar ratio of C₈H₁₈ to O₂ is 1:12.5.
- The mole fraction of O₂ in air is 0.21.
- The molar mass of air is 28.96 g/mol.
50 L of isooctane require the following mass of air.
