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Reptile [31]
3 years ago
15

Assuming all volume measurements are made at the same temperature and pressure, how many liters of oxygen gas would it take to r

eact completely with 7.25 liters of hydrogen gas? show all of the work used to solve this problem. balanced equation: 2h2 (g) + o2 (g) yields 2h2 o(g)
Chemistry
1 answer:
tatiyna3 years ago
7 0
You don't have to worry about converting to moles and back to liters. You need to know about Gay-Lussac's law of combining volumes. Coupled with Avogadro's law which says that the moles of gas are proportional to the volume, all we have to do is:

2H2(g) + O2(g) -> 2H2O(g)
2L ..........1L ..........2L
7.25L .....3.63L .....7.25L

The only work is dividing 7.25 by 2. 
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A dialysis unit requires 70000 mL of distilled water. How many gallons of water are needed? (1 gal = 4 qt)
Lady bird [3.3K]

Answer: 19.25 gallons

Explanation: 1 ml = 0.0011 quart

Given:  4 quarts = 1 gallon

Thus if 1 ml is equal to 0.0011 quart

70000 ml  is equal to =\frac{0.0011}{1}\times 70000=77quart

Now if 4 quarts is equal to 1 gallon.

77 quarts is is equal to=\frac{1}{4}\times 77=19.25gallons




5 0
3 years ago
Read 2 more answers
The element N (nitrogen) is an example of a ___
mina [271]

Hello!

Elements are made up of atoms, and elements combine to make compounds. Compounds are made up of molecules, and molecules are made up of atoms.

Nitrogen is an element. It could be made up of one or many atoms. A mixture is made up of compounds, so it is not the answer.

Molecules and compounds are made up of different atoms and elements, but nitrogen is not a molecule or a compound.

There is such a thing as a nitrogen atom, though.

Therefore, your answer would be 2) Atom.

I hope this helps!

6 0
3 years ago
Which of the following masses is the greatest?
GarryVolchara [31]

Answer:

4.2 gigagrams

Explanation:

kilo = 1,000

giga = 1,000,000,000

milli = .001

6 0
3 years ago
Which equation is balanced using the correct formulas and coefficients?
Sergio [31]
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3 0
3 years ago
Read 2 more answers
The colligative molality of an unknown aqueous solution is 1.56 m.
yawa3891 [41]

Answer:

Vapor pressure of solution = 17.02 Torr

T° of boiling point for the solution is 100.79°C

T° of freezing point for the solution is -2.9°C

Explanation:

Let's state the colligative properties with their formulas

- <u>Vapor pressure lowering</u>

ΔP = P° . Xm . i

- <u>Boiling point elevation</u>

ΔT = Kb . m . i

-<u> Freezing point depressión</u>

ΔT = Kf . m . i

ΔP = Vapor pressure pure solvent (P°) - Vapor pressure solution

ΔT = T° boling solution - T° boiling pure solvent

ΔT = T° freezing pure solvent - T° freezing solution

i represents the Van't Hoff factor (ions dissolved in the solution). If we assume that the solute is non-volatile and the solution is ideal i = 1

Kf and Kb are cryoscopic and ebulloscopic constant, they are  specific to each solvent.

Vapor pressure works with mole fraction (Xm) and the only data we have is molality, so we consider 1.56 moles of solute and 1000 g of solvent mass.

Moles of solvent → solvent mass / molar mass of solvent

Moles of solvent → 1000 g / 18 g/mol = 55.5 moles

Mole fraction is moles of solute / Total moles (mol st + mol sv)

Mole fraction: 1.56 / (1.56 + 55.5) = 0.027

- Vapor pressure lowering

ΔP = P° . Xm . i

17.5 Torr - Vapor pressure of solution = 17.5 Torr . 0.027 . 1

Vapor pressure of solution = - (17.5 Torr . 0.027 . 1 - 17.5 Torr)

Vapor pressure of solution = 17.02 Torr

- Boiling point elevation

ΔT = Kb . m . i

T° boiling solution - 100° = 0.512 °C/ m . 1.56 m . 1

T°boiling solution = 0.512 °C/ m . 1.56 m . 1 + 100°C

T°boiling solution = 100.79°C

- Freezing point depression

ΔT = Kf . m . i

0°C - T° freezing solution = 1.86 °C/m . 1.56 m . 1

T° freezing solution = - (1.86 °C/m . 1.56 m)

T° freezing solution = -2.9°C

3 0
4 years ago
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