There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Answer:
58
Step-by-step explanation:
As there are 12 teams in the league and each teams plays every other team twice per season. so, the total number of matches in the league will be 132.
let the matches won by home team = 'x'
given,
number of matches drawn = 34
matches won by the away team = x - 18
Now, according to the question,
⇒ total matches = matches drawn + matches won by home team + matches won by away team
⇒ 132 = 34 + x + x -18
⇒ x = 58
(40 * 25) + 0.10x = (40 * 20) + 0.20x
1000 + 0.10x = 800 + 0.20x
1000 - 800 = 0.20x - 0.10x
200 = 0.10x
200/0.10 = x
2000 = x <=== weekly sales must be $ 2000
