1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ladessa [460]
4 years ago
7

Is the slight bending of light as it passes around the edge of an object.

Chemistry
1 answer:
Snezhnost [94]4 years ago
7 0
The answer to the question Retraction. Its because the light goes around it
You might be interested in
In the electron cloud model, if you begin at the electron shell closest to the nucleus of an atom and move out, what is the numb
Serga [27]
Option B: 2, 8, 18, 32.

2 in the K shell, 8 in L shell, 18 in M shell and 32 in N shell.
8 0
3 years ago
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.892 M and [Fe2 ] = 0.0150
Effectus [21]

<u>Given:</u>

Concentration of Cr2+ = 0.892 M

Concentration of Fe2+ = 0.0150 M

<u>To determine:</u>

The cell potential, Ecell

<u>Explanation:</u>

The half cell reactions for the given cell are:

Anode: Oxidation

Cr(s) ↔ Cr2+(aq) + 2e⁻                E⁰ = -0.91 V

Cathode: Reduction

Fe2+ (aq) + 2e⁻ ↔ Fe (s)              E⁰ = -0.44 V

------------------------------------------

Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)

E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V

The cell potential can be deduced from the Nernst equation as follows:

Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]

Here, n = number of electrons = 2

Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V

Ans: The cell potential is 0.418 V

8 0
3 years ago
Read 2 more answers
Solve it and get 50 points​
den301095 [7]
Im not sure but my answer is c
8 0
3 years ago
Construct a simulated 1H NMR spectrum for 1-chloropropane by dragging and dropping the appropriate splitting patterns into the b
NARA [144]

Complete Question:

Check the first first file inserted

Answer:

Concepts and reason

This problem is based on the concept of Nuclear magnetic resonance which involves the absorption of radiations in the radio frequency region. This spectroscopy is generally used for the determination of the type and number of protons present in a molecule.  

Fundamentals

A spinning charge creates a magnetic field and therefore behaves as a tiny magnet . The spinning nuclei generate a magnetic field on exposure to an external magnetic field . If an external magnetic field is applied , spinning nuclei can get oriented in two ways:  

The magnetic field due to nuclei is in the same direction as the external field. In this case, the nuclei are said to be in a low energy spin state.

The magnetic field due to nuclei is in the opposite direction as the external magnetic field. In this case, the nuclei are said to be in high -energy spin state.

others inserted files gives additional and detailed information

6 0
3 years ago
1. Caused by movement of rocks<br>below the surface. is Called?​
valentina_108 [34]
I don’t know what to do with the answer I don’t know how you feel sorry I didn’t
3 0
3 years ago
Other questions:
  • Which two formulas contain 4 atoms of hydrogen
    10·2 answers
  • How fast does ethane(C2H6)) gas travel compare to chlorine gas
    7·1 answer
  • What is the oxidation number of the chloride ion in HClO ?
    8·1 answer
  • The process by which cells divide is called
    10·1 answer
  • How do I calculate Molar Mass
    7·1 answer
  • The diagram shows the electron configuration of an atom of an element for the electrons in the s and p orbitals.
    12·1 answer
  • 5. The density of a gas is lower than the density of a liquid because:
    14·1 answer
  • Atoms form ions by gaining or losing valence electrons to reach a more stable electron configuration with a full valence shell.
    9·1 answer
  • What is the position of the earth, moon, and sun during a new moon?
    5·2 answers
  • Why does lithium form a 1 ion?.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!