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Mumz [18]
3 years ago
6

A cube has a volume of 1/8 cubic meter. Complete the explanation for finding the length of each side of the cube. Express your a

nswers as simplified fractions when necessary. The length of the side of the cube is m; find a fraction that, when multiplied by itself
times, equals
Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

Volume of a cube= 1/8  cubic meter

We know that volume of a cube= side x side x side

(side)^{3}= \frac{1}{8}

From here, we get side of cube= \frac{1}{2} meter

Hence, the side of a cube =     \frac{1}{2} meter

We have to find a fraction, when it is multiplied by itself

\frac{1}{2} x \frac{1}{2}  = \frac{1}{4}

Here we get our answer  \frac{1}{4}

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3 0
3 years ago
Need by TONIGHT please help
igor_vitrenko [27]
Slope = 1/2 :) 
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7 0
3 years ago
Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx
Feliz [49]
Your question seems a bit incomplete, but for starters you can write

\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}

Expanding where necessary, recalling that (1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x, you have

\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x

Now, since 1+\tan^2x=\sec^2x, the final form could also take

\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1

or

\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x
7 0
4 years ago
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astra-53 [7]
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4 0
3 years ago
Are all this question statistical?
Mnenie [13.5K]
No, not all of these questions are statistical.

The first question does Mary like snacks is a Yes or No question which doesn't provide any statistics.
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3 years ago
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