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tester [92]
3 years ago
9

Solve this problem by using variation of parameters method. y''-y=coshx.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
y''-y=0\implies r^2-1=0\implies r=\pm1
\implies y_c=C_1e^x+C_2e^{-x}={C^*}_1\underbrace{\cosh x}_{y_1}+{C^*}_2\underbrace{\sinh x}_{y_2}

For the nonhomogeneous ODE

y''-y=\underbrace{\cosh x}_{f(x)}

we're looking for a particular solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\int\frac{y_2(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the two fundamental solutions.

We have

W(y_1,y_2)=\begin{vmatrix}\cosh x&\sinh x\\\sinh x&\cosh x\end{vmatrix}=\cosh^2x-\sinh^2x=1

so we're left with

u_1=-\displaystyle\int\sinh x\cosh x\,\mathrm dx=-\dfrac12\cosh^2x
u_2=\displaystyle\int\cosh^2x\,\mathrm dx=\dfrac12x+\dfrac14\sinh2x

so that the particular solution is

y_p=-\dfrac12\cosh^3x+\dfrac12x\sinh x+\dfrac14\sinh x\sinh2x
y_p=-\dfrac12\cosh x+\dfrac12x\sinh x

As y_1 already accounts for the \cosh x term in y_p, we're left with the general solution

y=C_1\cosh x+C_2\sinh x+\dfrac12x\sinh x
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NO LINKS. Find the segment length indicated. Assume that lines which appear to be tangent are tangent. PLEASE SHOW WORK!!​
algol13

Answer:

? = 9.2

Step-by-step explanation:

The angle between a tangent and radius at the point of contact is 90°

Then the triangle shown is right with legs ? , 6.9 and hypotenuse = (6.9 + 4.2) = 11.5

Using Pythagoras' identity in the right triangle

?² + 6.9² = 11.5²

?² + 47.61 = 132.25 ( subtract 47.61 from both sides )

?² = 84.64 ( take the square root of both sides )

? = \sqrt{84.64} = 9.2

7 0
2 years ago
Read 2 more answers
Find the volume of each question in the picture:
Kisachek [45]

Answer:

21.V=1746.1

22.V=1922.7

23.V=54.4

Step-by-step explanation:

V=h*w*l                V=pir^2*h

V=12*8*14 .           V=pi*4^2*8

V=1344 .               V=402.1

V1+V2=1344+402.1=1746.1

V=pi*r^2*h             V=2/3*pi*r^3

V=pi*6^2*13           V=2/3*pi*6^3

V=pi*36*13             V=2/3*pi*216

V=1470.3                V=452.4

V1+V2=1470.3+452.4=1922.7

V=1/3pi*r^2*h           V=1/3pi*r^2*h

V=1/3pi*2^2*6          V=1/3pi*2^2*7

V=8pi                       V=28/3pi

V=25.1 .                    V=29.3

V1+V2=25.1+29.3=54.4

8 0
2 years ago
If Frida has five friends who are available available to go to the movies with her but she only has four extra tickets how many
Fynjy0 [20]

Answer:

Step-by-step explanation: she only has 3 because of herself

3 0
3 years ago
Find the perimeter use 3.14
Alex777 [14]
Hey,
So we have to solve this in multiple steps. Step 1 is to find the circumference of the semi-circle and multiply by three since there are three. Step 2 would be to find the perimeter of the rectangle.  Step 3 would be to add those two together.

Step 1: To find the circumference of the semicircle use the formula pi (3.14) times radius (8 ÷ 2 = 4) times 2. After that we will divide by two since there is only half. After that we will multiply that answer by three.
C = 3.14 x 4 x 2
C = 12.56 x 2
C = 25.12

C = 25.12 ÷ 2
C = 12.56

Perimeter = 12.56 x 3 = 37.68

Step 2: To find the perimeter of the rectangle/square add all the sides (8).
Perimeter = 8 + 8 + 8 + 8 = 32

Step 3: Now add the two previous answers to get the final perimeter.
37.68 + 32 = 69.68

Final Answer: 69.68
Hope this helped!

Cheers,
Izzy

8 0
3 years ago
58635 divided by 59 equals what?? this awnser is very easy
Fynjy0 [20]
When i calculated it , it says 993.813
8 0
3 years ago
Read 2 more answers
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