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tester [92]
3 years ago
9

Solve this problem by using variation of parameters method. y''-y=coshx.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
y''-y=0\implies r^2-1=0\implies r=\pm1
\implies y_c=C_1e^x+C_2e^{-x}={C^*}_1\underbrace{\cosh x}_{y_1}+{C^*}_2\underbrace{\sinh x}_{y_2}

For the nonhomogeneous ODE

y''-y=\underbrace{\cosh x}_{f(x)}

we're looking for a particular solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\int\frac{y_2(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the two fundamental solutions.

We have

W(y_1,y_2)=\begin{vmatrix}\cosh x&\sinh x\\\sinh x&\cosh x\end{vmatrix}=\cosh^2x-\sinh^2x=1

so we're left with

u_1=-\displaystyle\int\sinh x\cosh x\,\mathrm dx=-\dfrac12\cosh^2x
u_2=\displaystyle\int\cosh^2x\,\mathrm dx=\dfrac12x+\dfrac14\sinh2x

so that the particular solution is

y_p=-\dfrac12\cosh^3x+\dfrac12x\sinh x+\dfrac14\sinh x\sinh2x
y_p=-\dfrac12\cosh x+\dfrac12x\sinh x

As y_1 already accounts for the \cosh x term in y_p, we're left with the general solution

y=C_1\cosh x+C_2\sinh x+\dfrac12x\sinh x
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If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²
astra-53 [7]

Answer:

Length of the rectangle  =25

width of the rectangle  = 20

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

             500 = x ( x+5)

          x² + 5 x = 500

      ⇒  x² + 5 x - 500 =0

      ⇒  x² +25x - 20 x - 500 =0

    ⇒  x( x+25) -20(x+25) =0

  ⇒  (x-20)(x+25) =0

 ⇒  x =20 and x=-25

we can choose x =20

<u><em>Step(iii):-</em></u>

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle  = 20

<u><em>Final answer</em></u>:-

Length of the rectangle  =25

width of the rectangle  = 20

3 0
3 years ago
Can I get all the right answers only
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Answer:

yes, you can get all right answers.

8 0
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A machine can produce a maximum of 600 parts per day. Yesterday, it produced 75 % of its maximum capacity. How many parts did th
gizmo_the_mogwai [7]

Answer:

450

Step-by-step explanation:

here is a fast way:

1- 75% = 75/100 = 3/4

2- 600 × (3/4) = 450

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The measure of angle B is 839, and the measure of angle C is 420.
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The square of a positive number is equal to its triple added to 28. What is this number?​
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hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

⊱┈────────────────────────┈⊰

\huge{ \rm{Answer:}}

The roots of the equation are 7 and -4, because 7 - 4 = 3 and 7. - 4 = -28

Step-by-step explanation:

The positive number is equal to 7.

Assuming that the number is equal to "x" we have:

\begin{gathered}x^2 = 3x + 28\\\\x^2 - 3x - 28 = 0\\\\a = 1\\\\b = -3\\\\c = -28\\\end{gathered}

By the sum and product method, we have:

\begin{gathered}S = -b / a\\\\S = -(-3) / 1\\\\S = 3\\\\\end{gathered}

\begin{gathered}P= c / a\\\\P = 28 / 1\\\\P = 28\\\\\end{gathered}

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2 years ago
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