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Reika [66]
3 years ago
11

. Let ????1 be the function that assigns to each nonnegative integer its last digit. Note: The nonnegative integers is the set o

f positive integers along with zero, or all of the integers except for the negative integers. What is the domain of ????1?
Mathematics
1 answer:
zalisa [80]3 years ago
3 0

The domain of a function is the complete set of possible values of the independent variable. In this case, the independent variable is any nonnegative integer. The nonnegative integers are the set of positive integers along with zero, then,

domain = {0, 1, 2, 3, ...} = natural numbers.

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Fazio chooses a jersey at random and then replaces it. He then selects a second jersey at random. What is the probability that f
Natalka [10]

Answer:

4% probability that fazio selects a striped jersey both times.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

For each jersey, there are 2+5+3 = 10 possible options, two of which are striped.

So twice 2/10

p = (\frac{2}{10})^{2} = \frac{4}{100}

4% probability that fazio selects a striped jersey both times.

5 0
3 years ago
What is a parralel line
Kryger [21]

Answer:

A parallel line is something that is equivalent on the other end. This mean if you cut a shape, a square for example, in half,the sides will be of equal length.

3 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
Apples cost a pence each.
Angelina_Jolie [31]

Answer:

\boxed{\sf \ \ 3a \ + \ 5b \ \ }

Step-by-step explanation:

hello

as an apple costs a pence and a banana b pence

3 apples + 5 bananas cost 3*a + 5*b

hope this helps

6 0
3 years ago
Read 2 more answers
5.82×10^2 can some one help me
alex41 [277]

5.82×10^2= 582

10^2= 10×10  10×10=100

5 0
3 years ago
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