Answer: y= 0.96 + 0.18x
Step-by-step explanation: I just did the assignment
You have to turn the denominators the same then whatever you do to the top you do to the bottom the just subtract
Answer:
$21.50
Step-by-step explanation:
Mr. Gutierrez had $100 to purchase candy for his students that completed their work.
He bought 8 bags of jolly ranchers
Each bag of jolly ranchers cost $3.25.
Hence, the cost of 8 bags of jolly ranchers = 8 × $3.25
= $26
He also bought 25 bags of assorted chocolate and each bag of assorted chocolate cost $2.10.
Hence, the cost of 25 bags of assorted chocolates = 25 × $2.10
= $52.5
Therefore, the amount of money Mr. Gutierrez has left over after these purchases is calculated as:
Total amount - Sum of ( Cost of 8 bags of jolly ranchers + 25 bags of assorted chocolates)
= $100 - ( $26 + $52.5)
= $100 - $78.50
= $21.50
Answer:
Its false because
Step-by-step explanation:
3250-1250=1500+2.(1250-500)
2000 = 1500 + 2 . 750
2000 = 1500 + 1500
2000 != 3000
Obviously 2000 isnt the same of 3000
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
