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2 years ago

Factorize (x-1)(x-2)(x-3)(x-4)+4

Mathematics

1 answer:

sleet_krkn [62]2 years ago

3 0

Answer:

Does not have any real roots.

Step-by-step explanation:

Fully expand: x^4 - 10x^3 + 35x^2 - 50x +28

Does not have any integer roots.

Does not have any real roots.

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3 years ago

Graph the function. y=-x-6 ifx<-6 y = 2x + 12 if x>-6

Naddik [55]

Answer:

see attached

Step-by-step explanation:

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2 years ago

Evaluate the expression for x = 4 1/3 9x + 4 A) 39 B) 40 C)43 D)52

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3 years ago

Read 2 more answers

What two numbers add to be 6 and multiply to be 15

yarga [219]

$\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct$

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3 years ago

How to calculate the are of a shape

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2 years ago

Factorize (x-1)(x-2)(x-3)(x-4)+4​

Factorize (x-1)(x-2)(x-3)(x-4)+4