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3 years ago

The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, g

bb, gbg, ggb, ggg}. After identifying the sample space for a couple having four children, find the probability of getting (one girl and three boys) in any order right parenthesis.

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

$|\Omega|=2^4=16\\|A|=4\\\\P(A)=\dfrac{4}{16}=\dfrac{1}{4}$

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The difference between the measures of two supplementary angles is 92. Find the measure of both angles

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x + y = 180

x - y = 92

---------------add

2x = 272

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3 years ago

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sasho [114]

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3 years ago

Ivan and Tanya share £150 in the ratio 4:1<br> How much more does Ivan get than Tanya

mina [271]

Answer:

Ivan gets £90 more than Tanya

Step-by-step explanation:

Given that

Total amount = £150

Ratio: 4:1

First of all we have to find the sum of ratio: 4+1 = 5

Now,

Ivan's Share:

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Tanya's Share:

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3 years ago

Please help!posted picture of question

Katen [24]

Answer:
b. 768

Explanation:
From the given sequence, we can note that we multiply each term by 4 to get the next one.
This is elaborated as follows:
3 * 4 = 12
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This means that the next term in the sequence would be 768

Hope this helps :)

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3 years ago

The sample space listing the eight simple events that are possible when a couple has three children is​ {bbb, bbg,​ bgb, bgg,​ g

The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, g