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2 years ago

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ONE OF THE FIRST WALKING ROBOTS HAD A TOP

1 answer:

vazorg [7]2 years ago

3 0

Answer:

? can you explain this a little better

Step-by-step explanation:

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Write an equation of the line that passes through a pair of points (-5, -2), (4, 5)

PIT_PIT [208]

To find the equation of a line knowing two points it passes through, we must first find the slope and then substitute the x and y values to figure out the y intercept.

First thing is to find the slope using the formula m = Δy ÷ Δx
m = 5 - (-2) ÷ 4 - (-5)

Now we simplify
m = 7 ÷ 9

Our equation so far is y = 7/9x + b. Now we can substitute the values of x and y from a point to figure out the answer. The equation here uses the point (4,5)

5 = 7/9 · 4 + b

Get b on one side
5 - 28/9 = b

Simplify
b = 1 + 8/9

That makes the equation of the line y = 7/9x + (1 + 8/9)

8 0

3 years ago

Read 2 more answers

To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work

liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = $\sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}$

So length AB = $\sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}$

BC= $\sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4$

AC = $\sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}$

Now perimeter = AB+BC+AC = $\sqrt{10}+4+3\sqrt{2}$

Plug in calculator

perimeter= 11.4 units

7 0

2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

2 years ago

What is the prime factorization of 28

SVETLANKA909090 [29]

$28|2\\14|2\\.\ 7|7\\.\ 1|\\\\28=2\times2\times7=2^2\times7$

5 0

2 years ago

Read 2 more answers

What is the Mean, Mode, and Median of this set? <br><br> 23, 34, 54, 43, 46, 27, 29

Alecsey [184]

43 is the median, the mean is 36.6 (36.57 rounded up) and since none of the numbers repeat, there isn't really a mode.
Hope this helps

3 0

3 years ago

Read 2 more answers