The first 5 terms in an arithmetic sequence is 4,2,0,-2,-4
Explanation:
The general form of an arithmetic sequence is
where a denotes the first term of the sequence, d denotes the common difference.
Here a = 4 and d = -2
To determine the consecutive terms of the sequence, let us substitute the values for n.
To find the second term, substitute n = 2 in the formula
Simplifying,
Similarly,
For n = 3,
For n = 4,
For n = 5,
Thus, the first 5 terms of the arithmetic sequence is 4,2,0,-2,-4
Answer:
C
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
