No the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y
Answer:
For any 2 real numbers all <em>algebric</em><em> </em><em>operations</em><em> </em><em>like</em><em> </em><em>+</em><em>,</em><em>-</em><em>,</em><em>×</em><em>,</em><em>÷</em><em> </em><em>are</em><em> </em><em>defined</em>
The answer would be 42
42*3 = 126
126+5 = 131
3(n)+5=131
3(n)+5 -5= 131-5
3(n)=126
3(n)/3= 126/3
n= 42
Equation:
y=6,000(1.05)^5
Answer:
7657
Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65
Then,
300 = k/65
k = 300*65 = 19500
Therefore,
For B = $145,
S= 19500/145 = $134.48
