(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]
= [{5^(x+1+x)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1-x)}/6]
= [{5^(x+1)}/6]Ans.
(c). 4a³b²
= 4(3)³(-2)²
Since, a = 3 and b = -2.
so,
= 4(3*3*3)(-2*-2)
= 4(27)(4)
= 108(4)
= 432Ans.
<u>also</u><u> </u><u>read</u><u> similar</u><u> questions</u><u>:</u> simplify 6/x-6+3x/x+5-1/(x-6)(x+5)..
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simplify the equation simplify x^5/8/x^1/6..
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All you have to do is plug and solve...
2(q+2) + 3q = -26
2q + 4 + 3q = -26
Subtract 4 from the left side and move it to the right...
2q + 4 + 3q = -26
- 4 - 04
_________________
2q + 3q = -30
Now add 3q and 2q together and you get 5q, next divide...
5q = -30
_______
5 5
Finally, you get q equal to negative 6 (-6)!
Answer:
5-6i
Step-by-step explanation:
The complex conjugate root theorem states that if (a+bi) is a root, then (a-bi) must also be a root and vice versa.
We know that (5+6i) is a root.
Then by the above theorem, (5-6i) must also be a root.
Hence, our solution is (5-6i).
Product is the answer you get when you multiply 2 numbers, so
3n + 5 < 2n - 7.
Answer: square root(265)
Step-by-step explanation:
Again, you can solve this via the Pythagorean theorem(a^2+b^2=c^2)
a= a side
b= another side
c= hypotenuse
Now, Substitute
12^2+11^2=x^2
144+121= 265
Now, square root and you get
square root(265)
