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ANTONII [103]
3 years ago
11

Solve this system by substitution, y = 1 -3x - 4y = 14 *Remember to write your answer as a coordinate point (x, y). 1​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
Step1- substitute 1 into the y
= -3x-4 x 1=14
=-3x -4=14
=-3x=14+4
=-3x=18
X=18/-3
X=-6


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alina1380 [7]

Answer: 2 < x < 16

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b-a < c < b+a

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b-a < c < b+a

9-7 < c < 9+7 .... replace a with 7, replace b with 9

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2 < x < 16 .... replace c with x

So x can be any number between 2 and 16. The value of x cannot be equal to 2. Also, x cannot be equal to 16 either.

8 0
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An um contains 1 red marble, 7 white marbles and 2 blue marbles. A player randomly
BaLLatris [955]

Answer:

A loss of 1.8$

Step-by-step explanation:

In the bag in this problem, we have:

r = 1 (number of red marbles)

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n = r + w + b = 1 + 7 + 2 = 10 (number of total marbles)

So, the probabilities of choosing a red, a white or a blue marble are:

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p(w)=\frac{w}{n}=\frac{7}{10}=0.7 (probability of choosing a white marble)

p(b) = \frac{b}{n}=\frac{2}{10}=0.2 (probability of choosing a blue marble)

The winning associated to each probability are:

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So the expected winning can be calculated as follows:

E(X)=p(r) \cdot (+\$5)+p(w) \cdot (-\$3) +p(b)\cdot (-\$1)=\\=(0.1)(+5)+(0.7)(-3)+(0.2)(-1)=-\$1.8

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enot [183]

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x=0

Step-by-step explanation:

The x has to be by themselves so get rid of the 5 and -6 - -6 equals 0

7 0
3 years ago
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Of the cartons produced by a​ company, 66​% have a​ puncture, 44​% have a smashed​ corner, and 0.50.5​% have both a puncture and
Xelga [282]

Answer:

0.095 or 9.5%

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The probability that a randomly selected carton has a puncture or a smashed corner is given by the probability of a puncture, added to the probability of a smashed corner, subtracted by the probability of both:

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2 years ago
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