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Hitman42 [59]
4 years ago
10

Please help in the 2nd question

Physics
1 answer:
Umnica [9.8K]4 years ago
7 0

Answer:

q=4\times 10^{-16}\ C

Explanation:

It is given that,

The charge on an object is 2500 e.

We need to find how many coulombs in the object. The charge remains quantized. It says that :

q = ne

q=2500\times 1.6\times 10^{-19}\ C\\\\q=4\times 10^{-16}\ C

So, the charge on the object is 4\times 10^{-16}\ C.

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URGENT!!!
madreJ [45]

Answer:

f=6.97\times 10^{14}\ Hz

Explanation:

Given that,

Wavelength, \lambda=430\ nm=430\times 10^{-9}\ m

We need to find the frequency of the violet light.

We know that the relation between frequency and wavelength is given by :

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{430\times 10^{-9}}\\\\f=6.97\times 10^{14}\ Hz

So, the frequency of violet light is 6.97\times 10^{14}\ Hz.

7 0
3 years ago
The student makes a single pile of the 500 sheets of paper. Which a metre rule, she measured the height of the pile. The height
Cerrena [4.2K]

Answer:  please see attached work.

Explanation:  please see attached work.  Assuming 500 sheets of paper = 20 lb.  (typicical value).  

6 0
3 years ago
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This
vova2212 [387]

Answer:

1.554\times 10^{32}\ \text{kg}

Explanation:

M = Mass of each star

T = Time period = 15.5 days

v = Orbital velocity = 230 km/s

G = Gravitational constant = 6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2

Radius of orbit is given by

R=\dfrac{vT}{2\pi}

We have the relation

\dfrac{Mv^2}{R}=\dfrac{GM^2}{(2R)^2}\\\Rightarrow M=\dfrac{4Rv^2}{G}\\\Rightarrow M=\dfrac{4\dfrac{vT}{2\pi}v^2}{G}\\\Rightarrow M=\dfrac{2v^3T}{\pi G}\\\Rightarrow M=\dfrac{2\times 230000^3\times 15.5\times 24\times 60\times 60}{\pi\times 6.674\times 10^{-11}}\\\Rightarrow M=1.554\times 10^{32}\ \text{kg}

The mass of each star is 1.554\times 10^{32}\ \text{kg}

6 0
3 years ago
How do u get rid of a hacker? plz help my friend needs this
Alja [10]
IP address then call the cops
3 0
3 years ago
Read 2 more answers
(a) How much work is required to lift a 35-kg object from the ground 3.0 m into the air? (b) How much gravitational potential en
V125BC [204]

Answer:

(a) work required to lift the object is 1029 J

(b) the gravitational potential energy gained by this object is 1029 J

Explanation:

Given;

mass of the object, m = 35 kg

height through which the object was lifted, h = 3 m

(a) work required to lift the object

W = F x d

W = (mg) x h

W = 35 x 9.8 x 3

W = 1029 J

(b) the gravitational potential energy gained by this object is calculated as;

ΔP.E = Pf - Pi

where;

Pi is the initial gravitational potential energy, at initial height (hi = 0)

ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)

ΔP.E = 1029 J

7 0
3 years ago
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