Answer:
The equilibrant force that will keep the object in equilibrium is;
A. 10 N to the left
Explanation:
The forces acting on the object are;
A 20 Newton force acting to pull the object horizontally to the left
A 30 Newton force acting to pull the object horizontally to the right
For equilibrium, we have;
The sum of forces acting on the object, ∑F = 0
Let '' represent the equilibrant force, with a convention of right = positive, we have;
At equilibrium, ∑F = 30 N - 20 N + = 0
∴ 30 N - 20 N + = 0
10 N = -
∴ = -10 N
With the convention that a force acting to the right = Positive, we have the equilibrant force, = -10 N which is negative, is acting towards the left;
∴ The equilibrant force that will keep the object in equilibrium, = 10 N acting to the left.
Given parameters:
Displacement = 8km
Velocity = 3.8km/h
Unknown:
time = ?
Solution:
Velocity is displacement divided by time.
Velocity =
Displacement = velocity x time
Input the parameters:
8 = 3.8 x time
Time = = 2.1s
The time taken is 2.1s
Answer:
R = 4Ω
Explanation:
If we have two resistors with resistances R1 and R2 in series the total resistance is R = R1 + R2
If the resistances are in parallel, the total resistance is given by:
1/R = 1/R1 + 1/R2.
First, we have a resistor with R1 = 1.5Ω
This resistor is connected in series with a parallel part (let's find the resistance of this parallel part), in one branch we have two resistors in series with resistances:
R2 = 8Ω and R3 = 4Ω
Because these are in series, the resistance of that branch is:
R = 8Ω + 4Ω = 12Ω
In the other branch, we have a single resistor of R4 = 4Ω
The resistance of the parallel part is:
1/R = 1/12Ω + 1/4Ω = 1/12Ω + 3/12Ω = 4/12Ω = 1/3Ω
1/R = 1/3Ω
R = 3Ω
Then we have a resistor (the first one, R1 = 1.5Ω) in series with a resistor of 3Ω.
Then the total resistance is:
R = 1Ω + 3Ω = 4Ω
The speed of sound at <span>0°C is approximately v=331.2 m/s. The frequency of the sound wave is f=990 Hz. To find the wavelength of the wave, we can use the basic relationship between frequency, wavelength and speed of a wave:
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<span>where </span>
is the wavelength. If we use the data of the problem, we find
The answer would be a nail rusting, but really it could be any of these.