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Harlamova29_29 [7]
3 years ago
15

Which, if any, of the following statements about electric field lines is/are true? A.The electric field is always perpendicular

to the surface outside of a conductor.
B.If an electron were placed on an electric field line, it would move in a direction perpendicular to the field.
C. Electric field lines originate on positive charge and terminate on negative charge.
D.It is possible for two electric field lines to cross each other.
E.If an electron and a positron were in the presence of a very strong electric field, they would move away from each other.
F.It is not possible for the electric field to ever be zero.
G.If a proton were placed on an electric field line, it would move in a direction anti-parallel to the field.
Physics
1 answer:
jonny [76]3 years ago
8 0
The electric field is always perpendicular to the surface outside of a conductor. TRUE

<span> If an electron were placed on an electric field line, it would move in a direction perpendicular to the field. FALSE, it would move in an anti-parallel direction because its charge is negative </span>
 
<span>Electric field lines originate on positive charge and terminate on negative charge. TRUE ; but they can also go to infinity </span>
 
It is possible for two electric field lines to cross each other.
<span> Usually FALSE; though technically possible at special points where field is zero. </span>
 
If an electron and a positron were in the presence of a very strong electric field, they would move away from each other.
<span> TRUE; one is positive, and one is negative. If the field is strong enough, the action of the field will overcome the mutual attraction between them </span>
 
It is not possible for the electric field to ever be zero. FALSE: it IS possible, inside a conductor for instance
   
If a proton were placed on an electric field line, it would move in a direction anti-parallel to the field.
<span> FALSE: being positive, it would move in the SAME direction as the field</span>ic 
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Multiple-Concept Example 6 reviews the concepts that play a role in this problem. A diver springs upward with an initial speed o
adell [148]

Answer:

Part a)

v_f = 7.99 m/s

Part b)

y = 3.25 m

Explanation:

Part a)

Since the diver is moving under gravity

so here its acceleration due to gravity will be uniform throughout the motion

so here we will have

v_f^2 - v_i^2 = 2 a y

here we have

v_i = 2.22 m/s

y = -3 m

v_f^2 - (2.22)^2 = 2(-9.81)(-3)

v_f = 7.99 m/s

Part b)

at highest point of his motion the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a (\Delta y)

0 - 2.22^2 = 2(-9.81)(y - 3)

y = 3.25 m

7 0
3 years ago
How do you solve for initial velocity?
nikdorinn [45]
Velocity is a function of time and defined by both a magnitude and a direction.  Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question. Sorry if this is not what your looking for
6 0
3 years ago
Someone pls answer this
andriy [413]

Answer:

<em>The speed of metal block B is 5 m/s after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, we have:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting the given values:

\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}

\displaystyle v'_2=\frac{8}{1.6}

\displaystyle v'_2=5\ m/s

The speed of metal block B is 5 m/s after the collision

8 0
3 years ago
A person runs 2 laps around a 400 meter track and stops where they initially
nalin [4]

The runner's total distance covered was 800 meters.  Her displacement (straight-line distance between start-point and end-point) was zero.

Her average speed = (distance)/(time) = 4.04 m/s

Her average <em>velocity</em> = (displacement) / (time) = <em>zero (choice - c)</em>

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3 years ago
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cluponka [151]

Answer:

glass is optically denser as it is a optical material having more index number above the list

3 0
2 years ago
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