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Harlamova29_29 [7]
3 years ago
15

Which, if any, of the following statements about electric field lines is/are true? A.The electric field is always perpendicular

to the surface outside of a conductor.
B.If an electron were placed on an electric field line, it would move in a direction perpendicular to the field.
C. Electric field lines originate on positive charge and terminate on negative charge.
D.It is possible for two electric field lines to cross each other.
E.If an electron and a positron were in the presence of a very strong electric field, they would move away from each other.
F.It is not possible for the electric field to ever be zero.
G.If a proton were placed on an electric field line, it would move in a direction anti-parallel to the field.
Physics
1 answer:
jonny [76]3 years ago
8 0
The electric field is always perpendicular to the surface outside of a conductor. TRUE

<span> If an electron were placed on an electric field line, it would move in a direction perpendicular to the field. FALSE, it would move in an anti-parallel direction because its charge is negative </span>
 
<span>Electric field lines originate on positive charge and terminate on negative charge. TRUE ; but they can also go to infinity </span>
 
It is possible for two electric field lines to cross each other.
<span> Usually FALSE; though technically possible at special points where field is zero. </span>
 
If an electron and a positron were in the presence of a very strong electric field, they would move away from each other.
<span> TRUE; one is positive, and one is negative. If the field is strong enough, the action of the field will overcome the mutual attraction between them </span>
 
It is not possible for the electric field to ever be zero. FALSE: it IS possible, inside a conductor for instance
   
If a proton were placed on an electric field line, it would move in a direction anti-parallel to the field.
<span> FALSE: being positive, it would move in the SAME direction as the field</span>ic 
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A 6 N force and a 15 N force act on an object. The moment arm of the 6 N force is 0.4 m. If the 15 N 20. force provides 5 times
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Answer:

0.8 m

Explanation:

For "6 N" force :

F = magnitude of the force = 6 N

r = moment arm = 0.4 m

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τ = (0.4) (6)

τ = 2.4 Nm

For " 15 N" force :

F' = magnitude of the force = 15 N

r' = moment arm = ?

τ' = Torque = 5 τ = 5 x 2.4 = 12 Nm

Torque due to "15 N" force is given as

τ' = r' F'

12 = r' (15)

r' = 0.8 m

So the moment arm for "15 N" force is 0.8 m

8 0
3 years ago
A piece of aluminum has a volume of 4.89 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6(C°)-1. The t
Leno4ka [110]

Answer:

11.515 Joule

Explanation:

Volume of aluminium = V = 4.89×10⁻³ m³

Coefficient of volume expansion for aluminum = α = 69×10⁻⁶ /°C

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Final temperature = 357°C

Pressure of air = 1.01×10⁵ Pa

Change in temperature = ΔT= 357-19.1 = 337.9 °C

Change in volume

ΔV = αVΔT

⇒ΔV = 69×10⁻⁶×4.89×10⁻³×337.9

⇒ΔV = 114010.839×10⁻⁹ m³

Work done

W = PΔV

⇒W = 1.01×10⁵×114010.839×10⁻⁹

⇒W = 11.515 J

∴ Work is done by the expanding aluminum is 11.515 Joule

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you can use one of your 5 senses to make _____ during an inquiry activity.

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