A guitar string is 0.620 m long, and

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5\,\dfrac{\text m}{\text s^2}0.5 s

Licemer1 [7]

The initial velocity of the bird before the gust of wind : <u>4 m/s</u>

<h3>Further explanation</h3>

An equation of uniformly accelerated motion

$\large {\boxed {\bold {x = xo + vo.t + \frac {1} {2} at ^ 2}}}$

v = vo + at

Vt² = vo² + 2a (x-xo)

x = distance on t

vo/vi = initial speed

vt/vf = speed on t /final speed

a = acceleration

Acceleration is a change in speed within a certain time interval

a = Δv /Δ t

$\displaystyle a=\frac{v2-v1}{t2-t1}$

Let complete the task :

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5 m/s² for 3 s. After the wind stops, the bird is flying to the right with a velocity of 2.5 m/s.

Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?

we can use formula :

vf = vi + a.t

vf = final velocity = 2.5 m/s

vi = asked

a = - 0.5 m/s²(leftward=negative)

t = 3 s

then :

$\displaystyle 2.5=vi-0.5.3\\\\vi=2.5+1.5\\\\vi=\boxed{\bold{4\frac{m}{s}}}$

<h3>Learn more</h3>

The car reach the end of the road

brainly.com/question/13750982

Keywords: uniformly accelerated motion, distance, velocity, acceleration

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7 0

3 years ago

Bowen’s reaction series illustrates relations between:

Finger [1]

C. Temperature, chemical composition and mineral structure

Explanation:

The Bowen's reaction series illustrates the relationship between temperature, chemical composition and mineral structure.

The series is made up of a continuous and discontinuous end through which magmatic composition can be understood as temperature changes.

The left part is the discontinuous end while the right side is the continuous series.
From the series, we understand that a magmatic body becomes felsic as it begins to cool to lower temperature.
A magma at high temperature is ultramafic and very rich in ferro-magnesian silicates which are the chief mineral composition of olivine and pyroxene. These minerals are predominantly found in mafic- ultramafic rocks. Also, we expect to find the calcic-plagioclase at high temperatures partitioned in the magma.
At a relatively low temperature, minerals with frame work structures begins to form . The magma is more enriched with felsic minerals and late stage crystallization occurs here.

Learn more:

Silicate minerals brainly.com/question/4772323

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5 0

4 years ago

A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a

xxTIMURxx [149]

Answer: $y_{com}=0.707 m$

$v_{com}=3.713 m/s$

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by first stone in 430 ms

$y_1=ut+\frac{at^2}{2}$

$y_1=0+\frac{g(0.43)^2}{2}$

$y_1=0.9069 m$

Distance traveled by stone 2 in t=430-59=371 ms

$y_2=ut+\frac{at^2}{2}$

$y_2=0+\frac{g(0.0.371)^2}{2}$

$y_2=0.674 m$

velocity of first stone after t=0.43 s

$v_1=u+at$

$v_1=0+9.8\times 0.43=4.214 m/s$

velocity of second stone after t=0.371 s

$v_2=u+at$

$v_2=0+9.8\times 0.371=3.63 m/s$

Position of Center of mass of system

$y=\frac{y_1m_1+y_2m_2}{m_1+m_2}$

$y=\frac{0.9069\times m+0.674\times 6m}{m+6m}$

$y=\frac{4.95m}{7m}=0.707 m$

Velocity of COM

$v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}$

$v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}$

$v_{com}=3.713 m/s$

6 0

4 years ago

Solve the equation<br> (2.40 x 10^7)* (3.10 x 10-5^-5)

Mariulka [41]

Explanation:

(2.40 × 10⁷) × (3.10 × 10⁻⁵)

(2.40 × 3.10) × (10⁷ × 10⁻⁵)

7.44 × 10²

7 0

4 years ago

Clothes in a dryer acquire static cling by

Gnoma [55]

<span>The answer is friction. The force acting upon the comparative motion of solid surfaces, liquid layers, and material elements sliding in contradiction of each other. When sides in contact move comparative to each other, the friction amid the two surfaces changes kinetic energy into thermal energy; in other words work to heat. </span>

5 0

3 years ago

Read 2 more answers