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3 years ago

5x-10x+ 2(3y-2)= 10y-5x + 4

1 answer:

6 0

5x-10x+ 2(3y-2)= 10y-5x + 4

Multiply 2 x 3y and by -2

5x-10x+6y-4=10y-5x+4

You get 6y-4

-5x+6y-4=10y-5x+4

Subtract 10x from 5x to get -5x

6y-4=10y+4

Add 5x to the -5x

6y=10y+8

Add 4 to the other side to get 8

-4y=8

Subtract 6y-10y to get -4y

-4y/-4=8/-4

Divide -4y and 8 by -4 to get y by itself and -2

Y=-2

Answer

Hope this helps

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Snezhnost [94]

Answer:

20 yd^2

Step-by-step explanation:

Your work is partially correct.

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3 years ago

Find the sum of the first 8 terms in the sequence 2 8 32 128

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3 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

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