Can someone please explain to me how to solve this problem?

The $48 that Frederick spent on books is equal to 1/2 the amount that he spent on books last week. Write an equation to figure o

aliina [53]

48=1/2b

Happy Easter!!!

3 0

3 years ago

Find -7a-6B (Picture provided)

sertanlavr [38]

Answer:

Option c

$-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -7A

$-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)$

Now we perform operation -6B

$-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)$

Now we add the resulting matrices

$\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

7 0

3 years ago

The low temperature on Monday was 6 degrees warmer than Sunday's low of -9°F.The low temperature on Tuesday was 3 degrees warmer

OverLord2011 [107]

Answer: the low temperature on Tuesday is 0 degree Fahrenheit

Step-by-step explanation:

The low temperature on Monday was 6 degrees warmer than Sunday's low of -9°F. This means that the temperature on Monday would be

- 9 + 6 = - 3 degrees Fahrenheit

The low temperature on Tuesday was 3 degrees warmer than Monday's low temperature. This means that the low temperature on Tuesday would be

- 3 + 3 = 0 degree Fahrenheit

5 0

3 years ago

Let line $l_1$ be the graph of $5x + 8y = -9$. Line $l_2$ is perpendicular to line $l_1$ and passes through the point $(10,10)$.

SashulF [63]

Answer:

m + c = - 4.4

Step-by-step explanation:

Line 1 is given by the equation 5x + 8y = -9, ⇒ $y = - \frac{5}{8} x - \frac{9}{5}$ ........(1) {In slope-intercept form}

If line 2 is perpendicular to the line 1 then the equation of line 2 will be

$y = \frac{8}{5} x + c$ ........ (2), where c is a constant. {Since the product of the slopes of two perpendicular straight line is -1}

Now, the line 2 passes through the point (10,10).

So, from equation (2), we get,

$c = y - \frac{8}{5} x = 10- \frac{8 \times 10}{5} = - 6$

Therefore, the equation of line 2 will be $y = \frac{8}{5} x - 6$

This equation is in y = mx + c form where $m = \frac{8}{5} = 1.6$ and c = - 6

Hence, m + c = 1.6 - 6 = - 4.4 (Answer)

7 0

3 years ago

Find the equation of a line with the given points.(put your answers in the form y=mx+b)(6,2)(5,5)

Nesterboy [21]

The slope-intercept form: y= mx + b

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (6, 2) and (5, 5). Substitute:

$m=\dfrac{5-2}{5-6}=\dfrac{3}{-1}=-3$

Therefore we have y = -3x + b.

Put the coordinates of the point (5, 5) to the equation:

5 = -3(5) + b

5 = -15 + b add 15 to both sides

20 = b

<h3>Answer: y = -3x + 20</h3>

6 0

3 years ago

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