to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.
For the limit approaching 3 from the right, you want to follow the line to the right of x = 3. From the graph you're describing it sounds like that's y = -3.

The RHS limit is -3 even though f(3) = 7
Step-by-step explanation:
let say he sold 5 bagels then he would sell 5 bagels
12-5=7 , b=7
replace in 12-5=7
b=12-s
Answer:
.50 sence per bag im sure?
Step-by-step explanation: