Let 
denote the rocket's position, velocity, and acceleration vectors at time 
.
We're given its initial position
and velocity
Immediately after launch, the rocket is subject to gravity, so its acceleration is
where 
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,
(the integral of 0 is a constant, but it ultimately doesn't matter in this case)
and
b. The rocket stays in the air for as long as it takes until 
, where 
is the -component of the position vector.
The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):
c. The rocket reaches its maximum height when its vertical velocity (the -component) is 0, at which point we have
Answer:
Step-by-step explanation:
1. -7 = w + 5
w = -12
(-12 + 5 = -7)
2. -4p + 38 = 10
-38 -38
-4p = -28
/-4 /-4
p = 7
3. -3 1/2 = -1 1/4b
/1.25 /1.25
-2 4/5 = -b
2 4/5 = b
or
2.8 = b
You would use order of operations: PEMDAS
P(parenthesis) E(exponents) MD(multiplication/division) AS(addition/subtraction)
with MD and AS order doesnt matter.
8(5-32) you would start with inside the Parenthesis for "P" so (5-32)=(-27)
next you would go to the E but because you dont have an exponent you go to the next step with is the "MD" you have multiplication so next would be 8(-27) and 8 multiplied by -27 is: 8(-27)= -216
ANSWER: -216
This is a vertical parabola, because (x-1)².
Vertex of the parabola (1,1).
So line symmetry is x=1.
Answer: -16
Step-by-step explanation:
Let the number be y
Four times a number minus twenty-one can be written as:
(4 × y) - 21 = 4y - 21
Six times the number plus eleven can be written as:
(6 × y) + 11 = 6y + 11
Combining both equations will give:
4y - 21 = 6y + 11
4y - 6y = 11 + 21
-2y = 32
y = 32/-2
y = -16
The number is -16
