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makkiz [27]
3 years ago
12

Kelly has a recipe for muffins that asks for 1 1/2 cups of sugar. She wants to use half that amount of sugar. How much sugar wil

l she use?
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

answer:

3/4 cups of sugar

Explanation:

turn 1 1/2 into a number which is 1.5 divide that by 2 which is .75 now turn that into a fraction and you get the answer 3/4 cups of sugar

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What is the area of a triangle h=5 b=6
soldi70 [24.7K]

Answer:

The answer is 15

Step-by-step explanation:

area of triangle is half * base * height

So 1/2*5*6 is 15

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2 years ago
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Joseph's lunch at a restaurant costs 13.00, without tax. He leaves the waiter a tip of 17% of the cost of the lunch, without tax
Musya8 [376]

Answer:

The cost before tax with tip is $15.21.

Step-by-step explanation:

To calculate percentage, take the percent (17%) and take its decimal form. This means 17% is 0.17 (like 50% would be 0.5). multiply the number you want the percentage of by the decimal form. 13*0.17=2.21. Add this to the cost before tax and before tip. 13.00+2.21=15.21. The cost before tax with tip is $15.21.

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2 years ago
The line plot shows the number of runners on a track team who won at least one gold medal.
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Answer:

1,3,10

Step-by-step explanation:

I got it wright on the test.

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3 years ago
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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were​ born, a
Bas_tet [7]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

b)Yes, the proportion of girls is significantly different from 0.5.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In the study 340 babies were​ born, and 289 of them were girls. This means that n = 340, \pi = \frac{289}{340} = 0.85

Use the sample data to construct a 99​% confidence interval estimate of the percentage of girls born.

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be ​effective?

b)Yes, the proportion of girls is significantly different from 0.5.

4 0
2 years ago
(2+3) Second power-16 divided by2
IgorC [24]

(2+3)^2-16÷2 is equal to 17

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