25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
8
Step-by-step explanation:
plug in the number 4, it would be 5•4-12
Do 5•4=20
20-12=8
Answer:
The warehouse will need 40 solar panels
Step-by-step explanation:
3/5 kilowatts is generated by 1 solar panel
24 kilowatts will be generated by ?
24 ÷ 3/5 = (24×5)/3 = 120/3 = 40 solar panels.
Answer:
= 20n + 12
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 52 - 32 = 72 - 52 = 92 - 72 = 20
This indicates the sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 32 and d = 20, thus
= 32 + 20(n - 1) = 32 + 20n - 20 = 20n + 12
I got -19/655 and i know for sure this isnt the correct answer.
