Suppose that first-, second-, and third-place winners of a contest are to be selected from eight students who entered. in how ma
ny ways can the winners be chosen?
1 answer:
As, order is important so we use permutation,
total no. of students= n=8
selected students= r=3
nPr= n!/(n-r)! = 8!/(8-3)! =336 different ways
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