Which set of data has the same mode and median?

1 answer:

5 0

Median is the middle number and you have to put each set in order like you've done, tick each number off and each side working in:
3,4,-6-,7,8 =6
3,3,-4-,5,5 =4
6,7,-7-,8,9 =7
2,2,-3-,4,6 =3
Mode is the number that shows up the most
3,4,6,7,8= no mode
3,3,4,5,5= 3 and 5
6,7,7,8,9=7
2,2,3,4,6=2

6,7,7,8,9 both have 7 for mode and median

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Public opinion in the large city of Bedrock is that 60 percent of the residents are in favor of increasing taxes to fund alterna

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Answer: 0.8461

Step-by-step explanation:

Let p be the proportion of residents are against the increase of taxes to fund alternatives to drug addiction treatment.

As per given , we have p=0.40

A random sample is taken with size : n= 400

Expecting sample proportion : $\hat{p}=\dfrac{150}{400}=0.375$

Now , the probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed will be :

$P(p>0.375)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})$

$=P(z>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})\ \ [\because\ z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]$

$=P(z>-1.02)=P(z-z)=P(Z$

$\approx0.8461$ [By z-table]

Hence, the approximate probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed is 0.8461 .

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4 years ago

In early spring, you buy 6 potted tomato plants for your container garden. The plants contained in 8 inch pots sell for $5 and t

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X - the number of plants in 8 in pots
y - the number of plants in 10 in pots

$x+y=6\\
5x+8y=36\\\\
x=6-y\\
5x+8y=36\\
5(6-y)+8y=36\\
30-5y+8y=36\\
3y=6\\
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4 plants in 8 in pots and 2 in 10 in pots.

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3 years ago

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$