Answer:
3200 ft-lb
Step-by-step explanation:
To answer this question, we need to find the force applied by the rope on the bucket at time 
At 
After seconds, the weight of the bucket is 
Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.
If the upward direction is positive, the displacement after seconds is 
Since the well is 80 ft deep, the time to pull out the bucket is 
We are now ready to calculate the work done by the rope on the bucket.
Since the displacement and the force are in the same direction, we can write
Use and 
![=\left[63 t-0.2 t^{2}\right]_{0}^{36}](https://tex.z-dn.net/?f=%3D%5Cleft%5B63%20t-0.2%20t%5E%7B2%7D%5Cright%5D_%7B0%7D%5E%7B36%7D)
Answer: 0.2 fam §(*￣▽￣*)§
99(x-77)=99(x+88)
99x-7623=99x+8712
99x-99x=8712+7623
0=670824.no solution as x becomes 0
Find the median of the following data:<br>
10,16, 15, 14, 8, 21, 10, 5, 19, 18, 4, 5, 16, 12, 10,9
fgiga [73]
Answer:
The median is 11.
Step-by-step explanation:
First arrange the data in ascending order:
4, 5, 5, 8, 9 , 10, 10, 10, 12, 14, 15, 16, 16, 18, 19, 21
There are 16 numbers so the median is the mean of the middle 2 numbers in the list. That is the mean of the 8th and ninth number.
Median = 10 + 12 / 2
= 11.
a) Phoenix is 85, Juneau is -23
-23 to 0 is 23, 0 to 85 is 85. 85 23 = 108 total degrees hotter.
b) Milwaukee was -7, the temperature rose 12 degrees.
-7 + 12 = 5
It was 5 degrees at noon.
