The answers are as follows:
a) F(A, B, C) = A'B'C' + A'B'C + A'BC' + A'BC + AB'C' + AB'C + ABC' + ABC
= A'(B'C' + B'C + BC' + BC) + A((B'C' + B'C + BC' + BC)
= (A' + A)(B'C' + B'C + BC' + BC) = B'C' + B'C + BC' + BC
= B'(C' + C) + B(C' + C) = B' + B = 1
b) F(x1, x2, x3, ..., xn) = ∑mi has 2n/2 minterms with x1 and 2n/2 minterms
with x'1, which can be factored and removed as in (a). The remaining 2n1
product terms will have 2n-1/2 minterms with x2 and 2n-1/2 minterms
with x'2, which and be factored to remove x2 and x'2, continue this
process until the last term is left and xn + x'n = 1
Search engine is a software to help find you results over the internet.
Examples of search engines are: Google, Safari, Yahoo etc.
In the case above, what just comes to mind as part of the process is option d.
<h3>What is sniffer?</h3>
A sniffer is known to be a kind of a software or hardware tool that gives room for a person to be able to “sniff” or look through one's internet traffic in real time, getting all the data flowing to and from a person's computer.
Therefore, In the case above, what just comes to mind as part of the process is option d.
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The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:
<h3>Python code</h3>
import datetime
inputs = []
result = []
#read the inputs
date = input()
inputs.append(date)
while not date == "-1":
date = input()
inputs.append(date)
#check if the input is in the correct format and convert it.
for date_text in inputs:
try:
date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")
result.append(date_text.strftime("%d/%m/%Y"))
except ValueError:
pass
print(*result, sep = "\n")
The above code would parse the string and extract the date. The split() method was used to break the input into tokens.
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