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alexira [117]
3 years ago
6

Help please. My last brain cell isn't cooperating.

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

A) 27, and 87 miles

B) 70,60,30

C) B=43,750, G=42,940, A=18,130

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60 POINTS!!!!!!!!!! If each square of the grid below is 0.5 cm by 0.5 cm, how many centimeters (cm) are in the perimeter of the
Aleks04 [339]

Answer:

21 cm

Step-by-step explanation:

The perimeter is the length of the outside of a shape. In this case, we can simply add up all the edges and multiply by .5(the length of one edge).

Horizontal Edges: 22

Vertical Edges: 20

Total: 42

Perimeter = 42 * 0.5 = 21 cm

8 0
3 years ago
Can someone help me with 3457 x 8392
kobusy [5.1K]

Answer:

29011144

Step-by-step explanation:

7 0
2 years ago
Please help I cant find the answer anywhere
DedPeter [7]
I am going to answer these from left to right.
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5 0
3 years ago
Which line has the greatest rate of change? A line passing through (-1, 4) and (1, 7). A line passing through (1, 3) and (5, 11)
Juliette [100K]

Answer:

A line passing through (1, 3) and (5, 11)

Rate of change = 2

Step-by-step explanation:

  • <em>Rate of change = change in y / change in x</em>
  • <em>r = Δy/Δx</em>

<u>Let's get the rate of change for each line:</u>

A line passing through (-1, 4) and (1, 7).

  • r = (7 - 4) / (1 -(-1)) = 3/2

A line passing through (1, 3) and (5, 11).

  • r =  (11 - 3) / (5 - 1) = 8/4 = 2

A line passing through (1, 1) and (4, -3).

  • r = (- 3 - 1) / (4 - 1) = -4/3

A line passing through (0, 6) and (12, 9)

  • r = (9 - 6) / (12 - 0) = 3/12 = 1/4

<u>Comparing the values of r, we can see the greatest one is</u> 2 for the line passing through (1, 3) and (5, 11)

6 0
4 years ago
Write the equation of the ellipse graphed below.
Lana71 [14]

Answer:

Step-by-step explanation:

This is a horizontally stretched ellipse.  That means that the horizontal line which is represented by the x-axis is the longer one.  The equation for this type of ellipse is

\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1

In an ellipse, the a value is ALWAYS bigger than the b value, and since the x-axis represents the longer axis, the a goes under the x-squared term.  

To solve for the h, the k, the a, and the b, we simply have to do some counting.  The center of the ellipse, the (h, k) our of equation, is sitting at (4, 6).  Put them where they belong in the equation.  The a axis (the horizontal one) is 8 units long, and the b axis (the vertical one) is 4 units long.  Square both of them and put them where they belong in the equation:

\frac{(x-4)^2}{64}+\frac{(y-6)^2}{16}  =1

There you go!

8 0
3 years ago
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