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bekas [8.4K]
3 years ago
15

A rectangular garden has dimension of 30 m by 20 m and divided in to 4 parts by 2 pathways that run perpendicular from its sides

. One pathway has width of 8 dm and the other, 7 dm . Calculate the total usable area of the garden. [1 dm = 0.1]

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0
The area depends on whether the 8dm path runs top to bottom or left to right
the followin solution will be for left to right

we need to draw a picture (see first attachment)

to simplify it, we can push the paths to the side (see second attachment)


now we can easily see that the usable area is the part not used by the paths
the width is 20-0.7=19.3
the height is 30-0.8=29.2

area=19.3*29.2=563.56 square meters



if it was frmo top to bottom
20-0.8=19.2
30-0.7=29.3
19.2*29.3=562.56 square meters



if the path is like in the attachments, then the usable area is 563.56 square meters
if the 7dm path and the 8dm path are switched, then the usable area is 562.56 square meters

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Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard
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Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean \mu and standard deviation \sigma

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: \mu_{V} = 525, \sigma_{V} = 100.

Math: \mu_{M} = 575, \sigma_{M} = 100

Combined:

\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100

\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

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3 years ago
Plsss help this is a math problem
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Two boxes are shaped as right rectangular prisms. The larger box is has a length of 24 cm, a width of 10 cm, and a height of 30
Vilka [71]
The dimensions of the smaller box are half those of the larger box. This means that:
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4 0
3 years ago
Please help!
Paraphin [41]
#1) A
#2) E
#3) C
#4) 0.5840
#5) 0.6945
#6) 0.4911
#7) D
#8) G
#9) 0.4375
#10) 0.5203

The formula we use for this is
v_w=f\lambda,
where v_w is the speed of sound, f is the frequency (or pitch) of the note, and λ is the wavelength.

#1) 0.77955f = 343

Divide both sides by 0.77955:
0.77955f/0.77955 = 343/0.77955
f = 439.997 ≈ 440. This is the pitch for A.

#2) 0.52028f = 343
Divide both sides by 0.52028, and we get f = 659.260.  This is the pitch for E.

#3) 0.65552f = 343
Divide both sides by 0.65552, and we get f = 523.25.   This is the pitch for C.

#4) 587.33λ = 343
Divide both sides by 587.33 and we get λ = 0.583999 ≈ 0.5840.

#5) 493.88λ = 343
Divide both sides by 493.88, and we get λ = 0.6945.

#6) 698.46λ = 343
Divide both sides by 698.46 and we get λ = 0.49108 ≈ 0.4911.

#7) 0.5840f = 343
Divide both sides by 0.5840 and we get f = 587.3288 ≈ 587.33.  This is the pitch for D.

#8) 0.4375f = 343
Divide both sides by 0.4375 and we get f = 784. This is the pitch for G.

#9) 783.99λ = 343
Divide both sides by 783.99 and we get λ = 0.4375.

#10) 659.26λ = 343
Divide both sides by 659.26 and we get λ = 0.52028 ≈ 0.5203.
6 0
3 years ago
The diameter of circle p below is 39.4 what is the approximate area of circle p???
Rufina [12.5K]
A= π r2 
<span>r= 39.4/2=19.7
A= 19.7 x 19.7=388.09
A= pi x 388.09= </span>1218.6026<span>
A= 1218.6026

</span>
3 0
3 years ago
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