A rectangular garden has dimension of 30 m by 20 m and divided in to 4 parts by 2 pathways that run perpendicular from its sides
. One pathway has width of 8 dm and the other, 7 dm . Calculate the total usable area of the garden. [1 dm = 0.1]
1 answer:
The area depends on whether the 8dm path runs top to bottom or left to right
the followin solution will be for left to right
we need to draw a picture (see first attachment)
to simplify it, we can push the paths to the side (see second attachment)
now we can easily see that the usable area is the part not used by the paths
the width is 20-0.7=19.3
the height is 30-0.8=29.2
area=19.3*29.2=563.56 square meters
if it was frmo top to bottom
20-0.8=19.2
30-0.7=29.3
19.2*29.3=562.56 square meters
if the path is like in the attachments, then the usable area is 563.56 square meters
if the 7dm path and the 8dm path are switched, then the usable area is 562.56 square meters
the followin solution will be for left to right
we need to draw a picture (see first attachment)
to simplify it, we can push the paths to the side (see second attachment)
now we can easily see that the usable area is the part not used by the paths
the width is 20-0.7=19.3
the height is 30-0.8=29.2
area=19.3*29.2=563.56 square meters
if it was frmo top to bottom
20-0.8=19.2
30-0.7=29.3
19.2*29.3=562.56 square meters
if the path is like in the attachments, then the usable area is 563.56 square meters
if the 7dm path and the 8dm path are switched, then the usable area is 562.56 square meters
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Answer:
where a>0.
To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.
Step-by-step explanation:
The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:
- zero -2 is factor (x+2)
- zero 1/2 is factor (2x-1)
- zero 3 is factor (x-3)
We write them together with an unknown leading coefficient a which is negative so -a.
where a>0
The leading coefficient of a polynomial determines the direction of the graph's end behavior.
- A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.
- A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.
- This graph has all odd multiplicity. The graph will cross through the x-axis each time at its real zeros.
To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.