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DochEvi [55]
3 years ago
8

A student was driving to school at 50 mph. A quarter of the way there he ran out of gas. If he ran the rest of the way at 10 mph

what was his average speed? Please explain as well.
Mathematics
1 answer:
sashaice [31]3 years ago
6 0

Answer:

Should be 40mph average

Step-by-step explanation:

If a student was driving 50mph a quarter of the way there, then 10mph the rest, that means that you can divide the drive like this. You have 4 parts of the drive, 3 of which are being drived at 50mph and the other at 10mph. You have to find the average using this equation.

(50+50+50+10)/4

160/4=40

lol i got way to complicated with this question ツ

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Answer:

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Step-by-step explanation:

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weeeeeb [17]

1. 4x + 2y = 11

x - 2 = -2y


First I would isolate one of the variables (x or y) of one of the equations, and then substitute it into the other equation.

The easiest to isolate is the "x" in the second equation

x - 2 = -2y  Add 2 on both sides

x = -2y + 2

Substitute this into the first equation


4x + 2y = 11

4(-2y + 2) + 2y = 11   Multiply 4 into (-2y + 2)

-8y + 8 + 2y = 11  Combine like terms

-6y + 8 = 11  Subtract 8 on both sides

-6y = 3   Divide -6 on both sides

y = -3/6  Simplify

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Now that you know "y", you can plug it into either of the original equations to find "x"

x - 2 = -2y

x - 2 = -2(-1/2)

x - 2 = 1    Add 2 on both sides

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Answer is A


2. y = 3x + 5

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Substitute the first equation into the second equation

4x - y = 5

4x - (3x + 5) = 5   Multiply/distribute the - into (3x + 5)

4x - 3x - 5 = 5  Combine like terms

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Plug in "x" into either of the original equations to find "y"

y = 3x + 5

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