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3 years ago

30 points + brainliest to answer with explanation.

Mathematics

2 answers:

Elan Coil [88]3 years ago

6 0

Answer:

sayin 30 points n you have five points up get out

Lesechka [4]3 years ago

6 0

Answer:

5 points nope!

Step-by-step explanation:

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Curtis paid $80 on the vet bill for his dog. Then the vet charged him $40 more for his dog's medicine. If he now owes the vet $1

Klio2033 [76]

Answer:

He paid 80 at the start, so his starting must have been 80

Step-by-step explanation:

80+40=120...

so either 0, or 80 because he owed nothing, or he owed the 80, then the 40 for medication

I hope this helps!

8 0

3 years ago

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What are two step equations

miskamm [114]

2 step equations are equations that require 2 steps to solve it.

For example, 2x + 5 = 3x + 6

To solve for x, we must isolate it.

First subtract 2x on both sides, which is ONE step.

2x + 5 = 3x + 6
-2x -2x

5 = x + 6

The we must subtract 6 from both sides of the equation, which makes is the second step.

5 = x + 6
-6 -6

-1 = x

-1 would be the answer and we only used 2 steps to solve it.

8 0

3 years ago

Simplify.<br><br><br> (1/2)^2−6(2−2/3)

Elena L [17]

Answer:

Exact form : -31/4

Decimal form: -7.75

mixed number form: -7(3/4)

Step-by-step explanation:

7 0

3 years ago

I NEED HELP WITH THIS ASAP

madreJ [45]

Answer:

I think its AED19

Step-by-step explanation:

please give brainliest if correct

3 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers