The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.
So, for a quadratic equation ax + bx + c = 0, the roots are

With a = 9, b = -6 and c = 5, the roots of our equation are

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.
So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
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Answer:
The third number is 195-3x
Step-by-step explanation:
Given:
sum of three numbers, a, b, c is 180.
a=2x-11
b=x-4
c= ?
Solution:
a+b+c = 180
2x-11 + x-4 + c = 180
c = 180 - (2x-11) - (x-4)
= 180 -2x+11 - x+4
= 180 + 11 + 4 -2x -x
= 195 -3x
-3=6m+5+4
add 5+4 = 9
-3=6m+9
subtract 9 from both sides
-12=6m
divide 6 from both sides
-2=m