<h2><u>EQUATION</u></h2><h3>Exercise</h3>
2(3 + 3y) + y = 11
First, apply the distributive property:
2(3 + 3y) + y = 11
6 + 6y + y = 11
6 + 7y = 11
Substract 6 from both sides:
6 - 6 + 7y = 11 - 6
7y = 5
Divide both sides by 7:
<h3><u>Answer</u>. The value of y = 5/7.</h3>
Answer:
4800m
Step-by-step explanation:
"correct to the nearest 10 meters" means that the height can vary ± 10 meters.
4810 m ± 10 m = 4800 to 4820
4800 is the least possible height.
Both the heads and tails will have a probability of 0.5 with a fair coin. ... TO find probability that foe the 7th toss head appears exactly 4 times.
Answer:
y=3/4x-2.5
Step-by-step explanation:
This is a straight line, so it would follow the equation y=mx+b. You can find the b value by looking at the y-intercept of the equation (where x=0), which in this case would be -2.5. Then, you can find the m value by comparing the two given points' locations. Slope is rise over run, so first you can find the rise. The y value moves from y=-4 to y=2, which is a value of 6 units upward. The points move from x=-2 to x=6, which is a distance of 8 units. Finally, put it into the rise over run pattern, giving you 6/8, which simplified is 3/4. This is your m value. Finally, plug in your two variable values into y=mx+b and you'll get y=3/4x-2.5.
Using it's concept, it is found that the sample mean package weight for Thursday is of 19 ounces.
<h3>What is the mean of a data-set?</h3>
The mean of a data-set is given by the <u>sum of the observations divided by the number of observations</u>.
For Thursday, the package weights in ounces are given by: {18, 19, 20, 19}.
Hence, the sample mean in ounces is of:
M = (18 + 19 + 20 + 19)/4 = 19.
More can be learned about the mean concept at brainly.com/question/24628525
