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3 years ago

Anyone want to get a conversation going again? lol

Physics

2 answers:

marshall27 [118]3 years ago

7 0

Hello

i am Marie

I lovee cat

loris [4]3 years ago

5 0

Quoth the Raven Nevermore.

You might be interested in

Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of

slavikrds [6]

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

3 0

3 years ago

Calculate the kinetic energy in joules of a 1500 kg automobile moving at 17 m/s . express your answer to two significant figures

Sidana [21]

Kinetic energy = 1/2 (mass)*(velocity)^2

ke = 1/2 (1500kg) (17m/s)^2
ke = 216750 kg*m^2/s^2 = 216750 Joules

(sorry, I don't know significant figures. but this is otherwise the correct answer with the right units. hope this helps!! :))

6 0

4 years ago

How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.

Sati [7]

Answer:

t = 3.35 s

Explanation:

It is given that,

Mass of a pumpkin, m = 8 kg

It is dropped from a height of 55 m

We need to find the time taken by it to hit the ground.

Initial velocity of the pumpkin, u = 0

Using second equation of motion to find it as follows :

$h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s$

So, it will take 3.35 seconds to hit the ground.

7 0

3 years ago

An experimenter using a gas thermometer found the pressure at the triple point of water (0.01°C) to be 4.80 × 10⁴ Pa and the pre

irakobra [83]

Answer:

$T = -282.33^o C$

Explanation:

As we know that the relation between temperature and pressure is a linear relation

so we have

$P - P_o = \frac{P_1 - P_o}{T_1 - T_o} (T - T_o)$

here we know that

$P_1 = 6.50 \times 10^4$

$P_o = 4.80 \times 10^4$

$T_1 = 100^o C$

$T_o = 0.01^o C$

now we will have

$P - 4.80 \times 10^4 = \frac{(6.50 - 4.80)\times 10^4}{100 - 0.01}(T - 0.01)$

$P = 4.80 \times 10^4 + 170.02(T - 0.01)$

now if P = 0

then we will have

$0 = 4.80 \times 10^4 + 170.02(T - 0.01)$

$T = -282.33^o C$

7 0

3 years ago

A delivery truck leaves a warehouse and travels 2.60 km north. The truck makes a right turn and travels 1.33 km east before maki

charle [14.2K]

Answer:

$AD\approx1.7582\ km$

Explanation:

Follow the schematic in which point A is the warehouse and point D is the destination.

Now we observe the triangle constructed $\Delta ADB$ :

here:

$AB\perp BD$

$AB=2.6-1.45$

$AB=1.15\ km$

$BD=1.33\ km$

As we know that displacement is the shortest distance between two points.

<u>Using Pythagoras theorem:</u>

$AD=\sqrt{AB^2+BD^2}$

$AD=\sqrt{(1.15)^2+(1.33)^2}$

$AD\approx1.7582\ km$

3 0

3 years ago