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tankabanditka [31]
3 years ago
10

Amit has found a rock in his backyard and would like to measure its mass, volume, and density. What tools can he use to perform

these measurements? meter stick, balance, and graduated cylinder graduated cylinder and balance meter stick and balance graduated cylinder and meter stick
Physics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer: a graduated cylinder and balance

A rock has an irregular shape. so, it would be difficult to measure using a meter stick. most convenient method to find the volume would be using a graduated cylinder. we can take a fixed volume of water in the cylinder. then drop rock into it. note the new raised volume. Subtract the initial volume from final to find the volume of rock.

Using balance, mass of the rock can be measured.

we can calculate the density using the following formula:

Density=\frac{Mass}{Volume}

Therefore, we need only two tools, a graduated cylinder and a balance to measure mass, volume and density of a rock.

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Its when both sides of a system are at the same temp. for example (sorry is this is a bad example) one of your hand was really cold and one was really hot from running it under hot water and you clamp your hands together the molecules in the hot hand (which are moving much faster due to the heat, will start bumping into the slow moving molecules in the cold hand, until it all balances out and both hands are the same temperature.

I hope the helps :)
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3 years ago
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What is one way to increase the amplitude of a wave in a medium?
kobusy [5.1K]

Answer:

A

Explanation:

Vibrations will always increase amplitude

7 0
4 years ago
Consider a mass initially moving at 7.50 m/s. How does it take to move 3.5 km (Be sure to convert to meters) if it accelerates a
Tomtit [17]
The mass is moving by uniformly accelerated motion, with initial velocity v_i=7.50 m/s and acceleration a=0.55 m/s^2. Its position at time t is given by the following law:
x(t)=v_i t + \frac{1}{2}at^2
where we take the initial position x_i=0 since we are only interested in the distance traveled by the mass.

If we put x(t)=d=3.5 km=3500 m into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
\frac{1}{2}at^2+v_it-d=0
4.9t^2+7.5t-3500 =0
And the two solutions for the equation are:
t=-25.5 s --> negative, we can discard it
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5 0
4 years ago
A firecracker sitting on the ground explodes into two pieces. Immediately after the explosion, one of the pieces has momentum of
Misha Larkins [42]

Answer:

other part will move with momentum 0.5 kg m/s towards west

Explanation:

As we know that the during the explosion event the time interval is very small and there is no impulsive force on the firecracker during this time

so here we can say that the momentum will remains conserved during the this event

now if the initial momentum of the firecracker is zero

then the final momentum must be zero

so here we can say

P_1 + P_2 = 0

P_1 = 0.5 kg m/s towards east

now from above equation

P_2 = - P_1 = -0.5 kg m/s

so the other part will move with momentum 0.5 kg m/s towards west

6 0
4 years ago
A flat loop of wire consisting of a single turn of cross-sectional area 8.20 cm2 is perpendicular to a magnetic field that incre
olga nikolaevna [1]

Answer:

The  induced current is I  =  6.25*10^{-4} \  A

Explanation:

From the question we are told that  

    The number of turns is  N  =  1

     The  cross-sectional area is  A  =  8.20 cm^2  =  8.20 * 10^{-4} \ m^2

    The  initial magnetic field is  B_i  =  0.500 \ T

     The  magnetic field at time =  1.02 s  is  B_t =  2.60 \ T

     The  resistance is  R  = 2.70\  \Omega

The  induced emf is mathematically represented as

       \epsilon  = - N  *   \frac{ d\phi }{dt}

The  negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

      Here  d\phi is the change in magnetic flux which is mathematically represented as

        d \phi  =  dB  *  A

Where  dB  is the change in magnetic field which is mathematically represented as

        dB  =  B_t  - B_i

substituting values

        dB  =   2.60 -  0.500

        dB  =   2.1 \ T

Thus  

      d \phi  =  2.1 * 8.20 *10^{-4}

     d \phi  = 1.722*10^{-3} \ weber

So  

     |\epsilon|  = 1   *   \frac{ 1.722*10^{-3}}{1.02}

     |\epsilon|  = 1.69 *10^{-3} \  V

The  induced current i mathematically represented as

      I  =  \frac{\epsilon}{ R }

  substituting values

       I  =  \frac{1.69*10^{-3}}{ 2.70 }

       I  =  6.25*10^{-4} \  A

7 0
4 years ago
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