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MakcuM [25]
3 years ago
13

A rigid body rotates about a fixed axis with a constant angular acceleration. Which one of the following statements is true conc

erning the tangential acceleration of any point on the body?
a. The tangential acceleration is zero m/s^2.
b. The tangential acceleration depends on the change in the angular velocity.
c. The tangential acceleration is constant in both magnitude and direction.
d. The tangential acceleration depends on the angular velocity.
e. The tangential acceleration is equal to the centripetal
Physics
1 answer:
Korolek [52]3 years ago
5 0

To solve this problem it will be necessary to apply the concepts related to angular acceleration and tangential acceleration. Definitions are given in the description of the angular kinematic movement and describe these two expressions of acceleration as:

The angular acceleration of the object is written as,

\alpha = \frac{\Delta \omega}{\Delta t}

The tangential acceleration is

a_T = \alpha r

Therefore equating the two previously expression we have,

a_T = \frac{\Delta \omega}{\Delta t} r

Here we can conclude that the angular acceleration depends on the change in angular velocity.

Therefore the correct answer is B.

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Answer:

Approximately 0.29\; {\rm m \cdot s^{-1}}.

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass m and velocity v is p = m\, v.

The momentum of the two trolleys before the collision would be:

  • 4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}.
  • 3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}.

Thus, the total momentum of the two trolleys right before the collision would be 2\; {\rm kg \cdot m \cdot s^{-1}}.

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}.

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass m = 7\; {\rm kg} would continue to be v = 2\; {\rm kg \cdot m \cdot s^{-1}} shortly after the collision.

Rearrange the equation p = m\, v to find the velocity of the two trolleys combined:

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}.

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The blades will push the air outside of the disk.There is no air in inside of the disc and  air pressure creates which  pushes air inside the disk to replace the missing air.

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Answer: 6s

Explanation:

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a= -6 m/s²  acceleration

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a=(Vf-Vs)/t

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