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3 years ago

Algebra help? question attached! will mark brainliest answer!

Mathematics

1 answer:

Monica [59]3 years ago

6 0

Is that i see you everywhere you go

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What is the value of x? x= units

attashe74 [19]

By Pythagoras theorem

$RQ^{2}= x^{2} + 16^{2}$
$RS^{2}= x^{2} + 9^{2}$

$SQ^{2}= RS^{2} + RQ^{2}$
$SQ^{2}= x^{2} + 16^{2} + x^{2} + 9^{2}$
$SQ^{2}=2 x^{2} +256+81$
$25^{2}=2 x^{2} +337$
$625-337=2 x^{2}$
$288=2 x^{2}$
$144= x^{2}$
$x=12$

8 0

3 years ago

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The sum of two segments are 75 cm, and one the segments are four times the other. Calculate the measurement of each segment

iVinArrow [24]

The length of one segment is 15 cm and other segment is 60 cm

Step-by-step explanation:

Let x be the length of one segment and y be the length of other segment

Then according to given statement

x+y=75 Eqn 1

And

one the segments are four times the other

x=4y Eqn 2

$Putting\ x=4y\ in\ equation\ 1$

$4y+y=75\\5y=75\\Dividing\ both\ sides\ by\ 5\\\frac{5y}{5}=\frac{75}{5}\\y=15\\Putting\ y=15\ in\ eqn\ 2\\x=4(15)\\x=60$

Hence,

The length of one segment is 15 cm and other segment is 60 cm

Keywords: Linear Equation, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

X+y=26 3x+8y=123 What is x equal

Pani-rosa [81]

Answer:

x=17, y=9. (17, 9).

Step-by-step explanation:

x+y=26

3x+8y=123

------------------

x=26-y

3(26-y)+8y=123

78-3y+8y=123

78+5y=123

5y=123-78

5y=45

y=45/5

y=9

x=26-9=17

5 0

3 years ago

A motorboat can go 16 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same

Katyanochek1 [597]

Answer:

A) d = 48t, d in miles, t in hours

B)d = 32t, d in miles, t in hours

C)y = 8 mph

Step-by-step explanation:

16 miles in 20 mins = 48 mph

16 miles in 30 mins = 32 mph

The boat speed is the average = (48 + 32)/2 = 40 mph

The current is the difference = 8 mph

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3 years ago

Which of the following is the best estimate of 31% of 15? 7.5 3 5 4

Alex777 [14]

Th answer is 5 because 31% of 15 is 4.65

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3 years ago

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