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Andre45 [30]
3 years ago
5

The equations 2 x minus y = negative 2, 3 x + 2 y = 5, 4 x minus y = 2, and 22 x + 10 y = 7 are shown on the graph below. On a c

oordinate plane, there are 4 lines. Green line goes through (0, 2.5) and (1.75, 0). Blue line goes through (0.5, 0) and (1, 2). Pink line goes through (negative 1, 0), and (0, 2). Purple line goes through (negative 0.75, 2.5) and (0, 0.75). Which system of equations has a solution of approximately (–0.3, 1.4)? 2 x minus y = negative 2 and 22 x + 10 y = 7 3 x + 2 y = 5 and 4 x minus y = 2 4 x minus y = 2 and 22 x + 10 y = 7 2 x minus y = negative 2 and 3 x + 2 y = 5

Mathematics
2 answers:
Molodets [167]3 years ago
7 0

Answer:

a

Step-by-step explanation:

did the test

KiRa [710]3 years ago
3 0

Answer:

<em>The correct answer is First option</em>:

22x+10y=7\\ 2x-y=-2

Step-by-step explanation:

We are given 4 equations:

22x+10y=7\\ 2x-y=-2\\3x+2y=5\ and\ \\4x-y=2

Let us solve the first two:

22x+10y=7...... (1)\\ 2x-y=-2 ...... (2)

Multiplying (2) with 10 and adding to (1):

22x+20x=7-20\\\Rightarrow 42x=-12\\\Rightarrow x = -0.2857 \approx -0.3

So, approximately, value of x is -0.3.

Putting value of x in (2):

2 \times -0.3 - y =-2\\\Rightarrow y = -0.6+2\\\Rightarrow y = 1.4

value of x is approximately -0.3 so y is approximately 1.4.

So, the solution is \approx (–0.3, 1.4)

<em>The correct answer is First option</em>:

22x+10y=7\\ 2x-y=-2

The above two equations have a solution <em>approximately (–0.3, 1.4).</em>

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