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Nadusha1986 [10]
2 years ago
14

Solve using the substitution method: 6x + y =15 4x + 3y = 31

Mathematics
1 answer:
Ksivusya [100]2 years ago
3 0

Answer:

the answers to this are x= 1 and y= 9

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9 x 10 to the power of 2 how many times as much as 3 x 10 to the -2 power
hjlf

Answer:

  3×10^4

Step-by-step explanation:

The desired factor is found by calculating the ratio of the two numbers:

  k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4

The first number is 3×10^4 = 30,000 times as much as the second number.

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2 years ago
Suppose parametric equations for the line segment between (6,9) and (0,0) have the form: x = a+bt y = c+dt If the parametric cur
olasank [31]

What is 0.05 Equal to 0.5.

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2 years ago
The cost of four cell phones are $345,$400,$110,and$640 What is the Median cost
garri49 [273]

Answer:

372.5

Step-by-step explanation:

Order the numbers least to greatest:

110, 345, 400, 640

Add the two middle numbers:

345+400= 745

Divide 745 by 2:

372.5

6 0
3 years ago
For which real numbers x and y is it true that x + y = x+y?
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By the general application of cumulative property of addition :

x + y = y + x

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6 0
3 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
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