Question

What is the radical form of the expression? (5x3y4)37 ↡

Answer 1

Option 4: $\sqrt[7]{125x^9y^{12}}$ is the right answer

Step-by-step explanation:

Given expression is:

$(\sqrt{5x^3y^4})^{\frac{3}{7}$

In order to convert an exponent into radical form, the power should be in the form of 1/x where x is any number

so,

in case of 3/7, it will be broken down

$(\sqrt{5x^3y^4})^{3*\frac{1}{7}}$

The 1/7 will be converted into base of radical while 3 will be he exponent

$\sqrt[7]{(5x^3y^4)^3}$

Multiplying exponents

$=\sqrt[7]{5^3x^{3*3}y^{4*3}}\\=\sqrt[7]{125x^9y^{12}}$

Hence,

Option 4: $\sqrt[7]{125x^9y^{12}}$ is the right answer

Keywords: Radicals, Exponents

Learn more about exponents at:

• brainly.com/question/4939434
• brainly.com/question/4980053

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