2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
There are 11 numbers on cards.
6 cards contain even numbers.
Answer: p(even) = 6/11
There is only one card with a 7. After the first card is picked and returned, there are 11 cards in the bag again.
p(even then 7) = p(even) * p(7) = 6/11 * 1/11 = 6/121
Answer: p(even then 7) = 6/121
1. To solve this exercise, you must use the "Intersecting chords theorem".
2. You have that:
AP=3.5 in
PC=6 in
DP=4 in
3. Then, by applying the "Intersecting chord theorem", you have:
(AP)(PC)=(BP)(DP)
4. When you substitute the values into (AP)(PC)=(BP)(DP), you obtain:
(3.5 in)(6 in)/BP(4 in)
5. Now, you must clear BP. Then:
(3.5 in)(6 in)/4 in=BP
21 in^2/4 in=BP
6. Therefore, the value of BP is:
BP=5.25 in
Answer:
3(n+4)
Step-by-step explanation:
you will take common
3(n+4)
9514 1404 393
Answer:
(b) √55
Step-by-step explanation:
The right triangles in this geometry are all similar, so the ratio of long side to short side is the same:
y/5 = 11/y
y² = 55 . . . . . . multiply by 5y
y = √55 . . . . . take the square root
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And x=4√5 by looking at ratios of short side to hypotenuse.
