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Stolb23 [73]
3 years ago
13

What is standard form in slope

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

When writing the equation of a line, you'll often

be asked to put that equation in standard form.

Standard form is written Ax + By = C where A, B, and C are all integers.

In other words, no fractions and A or the

coefficient of the x term must be positive.

So that a good example of an equation of a line

written in standard form might be 2x + 3y = 4.

tatyana61 [14]3 years ago
4 0

Answer:

The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers. We can convert a point slope equation into standard form by moving the variables to the left side of the equation.

Step-by-step explanation:


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Simultaneously x-2y=0 40-y=14​
harkovskaia [24]

Answer:

x = 52, y = 26

Step-by-step explanation:

x - 2y = 0

40 - y = 14​

(40 - 40) - y = 14​ - 40

- y = -26

y = 26

x - 2(26) = 0

x - 52 = 0

x (- 52 + 52) = 0 + 52

x = 52

7 0
3 years ago
What is the solution to this inequality?<br> x-6&lt;-4
9966 [12]

Answer:

x<2

Step-by-step explanation:

8 0
3 years ago
10 times as many as 100
mr Goodwill [35]
<span>10 times as many as 100
this simply mean 10<span>100
</span>=> 10 will be multiplies a 100 times and the result will be 1e100
=> also explained as 1 and 100 zeros to get the answer</span>



4 0
3 years ago
Can someone please help me
koban [17]

Answer:

x=\sqrt{y-1

Step-by-step explanation:

5 0
3 years ago
Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is &lt;) 3 if x is =0 -2 if x is &gt; 0
V125BC [204]

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

h(x) = -\frac{1}{3}x^2 + 4 --- x \ne 2

h(x) = -4 --- x= 2

Required

h(-5)\ \&\ h(2)

<u>Calculating h(-5)</u>

This implies that: x = -5

-5 \ne 2

So, we make use of:

h(x) = -\frac{1}{3}x^2 + 4

Substitute -5 for x

h(-5) = -\frac{1}{3} * (-5)^2 + 4

h(-5) = -\frac{1}{3} * 25 + 4

h(-5) = -\frac{25}{3} + 4

Take LCM

h(-5) = \frac{-25+12}{3}

h(-5) = -\frac{13}{3}

<u>Calculating h(2)</u>

This implies that: x = 2

2 = 2

So, we make use of:

h(x) = -4

Substitute 2 for x

h(2) = -4

<em>Use the above explanation to answer your question</em>

3 0
3 years ago
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