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3 years ago

How do you solve? 2/3 of 12

Mathematics

1 answer:

stealth61 [152]3 years ago

4 0

To solve 2/3 of 12 we need to divide 12 by 3 which is 4 so then we need to do 4 x 2 which is 8. Hope I helped.

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Mercury orbits the Sun in 87 24/25 earth days. Venus orbits the Sun in 224 7/10 earth days and Mars orbits the sun in 686 49/50

Rufina [12.5K]

87 24/25.......24/25 = 0.96......answer is 87.96

224 7/10....7/10 = 0.7....answer is 224.7

686 49/50...49/50 = 0.98...answer is 686.98

7 0

3 years ago

Simplify the expression below. 2x - 10 + 6x

PtichkaEL [24]

Answer:

8x - 10

Step-by-step explanation:

Combine like terms:

2x + 6x - 10

= 8x -10

4 0

3 years ago

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the population of staten island is 7.6*10^3. the population of Brooklyn is 2.3*10^5. how many people are there in Brooklyn and S

nydimaria [60]

7.6*10^3+2.3*10^5=7600+230000= 237600.

There are 237600 people living in Brooklyn and Staten Island.

7 0

3 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

11. On Halloween, 87.5% of the homes in a

fiasKO [112]

87.5% of 104
87.5% x 104 = 91 homes handed out candy

8 0

3 years ago

Read 2 more answers