6! = 6 * 5 *4*3*2*1 =720
8p5 = 8*7*6*5*4 = 6720
12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495
The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
Answer:
-1/2
Step-by-step explanation:
counting down by 2 over one
The answer is <span>0.00833333333</span>
Step-by-step explanation:
abcdefghijklmnopqrstu
