Elimination:
7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3
(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3
Substitution:
5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y
5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0
Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question
Answer:
C. Logan
Step-by-step explanation:
you divide the amount of problems by how many minutes it took each person. for example if you divide the amount of problems Logan did by how many minutes it took him. (84÷3) it equals 28.
Hello from MrBillDoesMath!
Answer:
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Discussion:
Given
64v^3 + 192v^2 - 56 v - 168
Factor 64v^2 from the first two terms. Factor 56 from the last two terms:
64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms
(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()
8(v+3)(8v^2-7) => factor 8y^2-7
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Thank you,
MrB
Answer:
The expectation of the policy until the person reaches 61 is of -$4.
Step-by-step explanation:
We have these following probabilities:
0.954 probability of a loss of $50.
1 - 0.954 = 0.046 probability of "earning" 1000 - 50 = $950.
Find the expectation of the policy until the person reaches 61.
Each outcome multiplied by it's probability, so:
The expectation of the policy until the person reaches 61 is of -$4.
Answer:
Step-by-step explanation:
t=3
