The closest is 0
Just plug that into a calculator
Answer:
The tank is a cone, so the radius of the cross section increases linearly with h
At y=0, r=4 and at y=11, r=0
So
r(y)=4/11 (11−y)
A(y)=π[4(11−y)11]^2
Integral will be:
11∫0 (1000)(9.8)(4πy^2)(25)(11−y)dy
Step-by-step explanation:
Answer:
a) 15-t mph;
b) 15+t mph.
Step-by-step explanation:
a) When the boat travels upstream, the current hinders the boat (the speed of the boat decreases). Thus, the speed of the boat upstream becomes
15-t mph.
b) When the boat travels downstream, the current helps the boat (the speed of the boat increases). Thus, the speed of the boat downstream becomes
15+t mph.
Answer: = 163823 x 9273^3/2. Hope this helps!
