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3 years ago

11

Five seventh-grade students are decorating 3 bulletin boards and want to divide the work equally. Will each student decorate mor

e than or less than 1 bulletin board? Explain how you know.

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

Less than 1 bulletin board.

Step-by-step explanation:

If they divide the work equally they each will decorate 3/5 = 3/5 of a board.

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If the ordered pair (a, b) satisfies the inequality. y > x-4, three of these statements are

Mumz [18]

Answer:

If you subtract 4 from a, it will be greater than b

Step-by-step explanation:

Ok, so in order to solve this, it would be easier to substitute (a,b) into the equation:

b>a-4

Ok, next, you just have to work out each individual question to see which one is incorrect. You can immediately know it is the first one, and this is because we know that B is larger in this equation, but the problem says that subtracting 4 from a would be greater than b. This is incorrect, b is greater than 4-a, so the top left would be your answer.

Hope this helps!

6 0

4 years ago

If x = 15 cm, y = 36 cm, and z = 39 cm, what is the surface area of the geometric shape formed by this net? A. 1,890 cm2 B. 2,88

zheka24 [161]

Answer:

I belive it’s C

Step-by-step explanation:

I don’t know if it’s correct tell me if I’m wrong

6 0

2 years ago

If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then

agasfer [191]

Answer:

smaller value is 1.2

larger value is 6

Step-by-step explanation:

$f(x)=\frac{3}{1+x^{2} }$

when x=a=0, one has

$f(0)=\frac{3}{1+0^{2} } \\f(0)=3$

now, when x=b=2, one has

$f(2)=\frac{3}{1+2^{2} } \\f(2)=\frac{3}{5}$

Therefore, the absolute minumun is

$m=\frac{3}{5}$

and the absolute maximun is

$M=3$

The approximation to the integral is

$\frac{3}{5}(2-0)\leq \int\limits^2_0 {f(x)} \, dx \leq 3(2-0)$

hence

$\frac{3}{5}(2)\leq \int\limits^2_0 {f(x)} \, dx \leq 3(2)\\\frac{6}{5} \leq \int\limits^2_0 {f(x)} \, dx \leq 6\\1.2 \leq \int\limits^2_0 {f(x)} \, dx \leq 6$

7 0

4 years ago

Which point is on the circle centered at the origin with a radius of 5 units? Distance formula: StartRoot (x 2 minus x 1) square

Sergeeva-Olga [200]

Answer:

Option A) $(2,\sqrt{21})$

Step-by-step explanation:

The following information is missing in the question:

A. $(2,\sqrt{21})$

B. $(2,\sqrt{23})$

C. (2, 1)

D. (2, 3)

We are given the following in the question:

A circle centered at origin and radius 5 units.

We have to find the equation of a point that lies on the circle.

Let (x,y) lie on the circle.

Distance formula:

$d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Putting

$(x_2,y_2) = (x,y)\\(x_1.y_1) = (0,0)\\d = 5$

We get,

$5 = \sqrt{(y-0)^2 + (x-0)^2}\\\sqrt{x^2+y^2}=5\\x^2+y^2 = 25$

is the required equation of point on the circle centered at the origin with a radius of 5 units.

The point $(2,\sqrt{21})$ satisfies the given equation.

Verification:

$(2)^2 + (\sqrt{21})^2\\=4 + 21\\=25$

Thus, $(2,\sqrt{21})$ lies on the circle centered at the origin with a radius of 5 units.

7 0

4 years ago

Read 2 more answers

A drawing of a garden uses a scale of 1 in 3 ft. Find the length of the drawing is 13 inches

bagirrra123 [75]

So we know each inch is 3 feet.

1:3.

13:?

So we multiply 13 by 3 to get the answer!

13:39

or 39 feet!

I hope this helped! :))

4 0

4 years ago