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beks73 [17]
2 years ago
9

Solve for r. √2/3r + 1 = 23

Mathematics
2 answers:
Keith_Richards [23]2 years ago
7 0

Answer:

2nd option

Step-by-step explanation:

\frac{\sqrt{2} }{3} r + 1 = 23 ( subtract 1 from both sides )

\frac{\sqrt{2} }{3} r = 22 ( multiply both sides by 3 to clear the fraction )

\sqrt{2} r = 66 ( divide both sides by \sqrt{2} )

r = \frac{66}{\sqrt{2} } × \frac{\sqrt{2} }{\sqrt{2} } ( rationalising the denominator )

r = \frac{66\sqrt{2} }{2} = 33\sqrt{2}

andriy [413]2 years ago
3 0

Answer:

B) r=33*sqrt(2)

Step-by-step explanation:

sqrt(2)/3r+1=23

sqrt(2)/3r=23-1

sqrt(2)/3r=22

sqrt(2)r=22*3

sqrt(2)r=66

r=66/sqrt(2)

r=66*sqrt(2)/(sqrt(2)*sqrt(2))

r=(66*sqrt(2)/2

r=33*sqrt(2)

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