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beks73 [17]
3 years ago
9

Solve for r. √2/3r + 1 = 23

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

2nd option

Step-by-step explanation:

\frac{\sqrt{2} }{3} r + 1 = 23 ( subtract 1 from both sides )

\frac{\sqrt{2} }{3} r = 22 ( multiply both sides by 3 to clear the fraction )

\sqrt{2} r = 66 ( divide both sides by \sqrt{2} )

r = \frac{66}{\sqrt{2} } × \frac{\sqrt{2} }{\sqrt{2} } ( rationalising the denominator )

r = \frac{66\sqrt{2} }{2} = 33\sqrt{2}

andriy [413]3 years ago
3 0

Answer:

B) r=33*sqrt(2)

Step-by-step explanation:

sqrt(2)/3r+1=23

sqrt(2)/3r=23-1

sqrt(2)/3r=22

sqrt(2)r=22*3

sqrt(2)r=66

r=66/sqrt(2)

r=66*sqrt(2)/(sqrt(2)*sqrt(2))

r=(66*sqrt(2)/2

r=33*sqrt(2)

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A mailbox that is 36 inches tall is beside a tree.The length of the mailboxes shadow is 28 inches.The length of the trees shadow
mixer [17]

Answer:

10.5 feet

Step-by-step explanation:

In this problem, we have two similar triangles:

- One consists of the mailbox, its shadow and the hypothenuse

- The other one consists of the tree, its shadow and the hypothenuse

The two triangles are similar, so they have same proportions between their sides: therefore, we can apply the rule of three:

\frac{m}{s_m}=\frac{t}{s_t}

where

m = 36 in is the height of the mailbox

s_m=28 in is the shadow of the mailbox

t is the height of the tree

s_t=98 in is the length of the shadow of the tree

Solving for t, we find the height of the tree:

t=\frac{m\cdot s_t}{s_m}=\frac{(36)(98)}{28}=126 in

And since

1 feet = 12 inches

The height of the tree in feet is

t=\frac{126}{12}=10.5 ft

3 0
3 years ago
What is √-11 in the form a+bi?
Mice21 [21]

Given:

The number is \sqrt{-11}.

To find:

The a+bi form of given number.

Solution:

We have,

\sqrt{-11}

It can be written as

\sqrt{-11}=\sqrt{-1\times 11}

\sqrt{-11}=\sqrt{-1}\times \sqrt{11}      [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

\sqrt{-11}=i\times \sqrt{11}      [\because \sqrt{-1}=i]

\sqrt{-11}=\sqrt{11}i

Here, real part is missing. So, it can be taken as 0.

\sqrt{-11}=0+\sqrt{11}i

So, a = 0 and b=\sqrt{11}.

Therefore, the a+bi form of given number is 0+\sqrt{11}i.

5 0
3 years ago
I have been stuck on this forever. Please help me
il63 [147K]
2a. speed= distance
---------------
time

60÷69 = 52.1739 miles per hour.



so for the next one with the airplane flies 296 km in 276 min is the same formula.
296/276 = 39.9839 mph.

I couldn't see the first question clear...sorry but apply same formula.
Hoping this will help you
5 0
3 years ago
A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 2780 seats. The students
Over [174]

Answer:

1242 6th graders went on the trip.

Step-by-step explanation:

From the information given, you know that the theater has 2760 seats and that the students filled 45% of the seats, so to find the quantity of 6th graders that went on the trip, you have to calculate 45% of 2760:

2760*45%=1242

According to this, the answer is that 1242 6th graders went on the trip.

5 0
3 years ago
Find the area of the region enclosed by the graph of $x^2 + y^2 = 2x - 6y + 6$
Luda [366]

Answer:

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Step-by-step explanation:

The equation is that of a circle of radius 4. The area of a circle is given by ...

  A = πr²

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_____

The equation can be put into the standard form for a circle to find its radius.

  (x^2 -2x) +(y^2 +6y) = 6 . . . . collect variable terms on the left

  (x^2 -2x +1) +(y^2 +6y +9) = 6 + 1 + 9 = 16 . . . . . complete the squares

  (x -1)^2 +(y +3)^2 = 4^2 . . . . . the radius is 4

Compare to the form ...

  (x -h)^2 +(y -k)^2 = r^2 . . . . circle of radius r centered at (h, k)

7 0
4 years ago
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