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4 years ago

Is 9,12,15 a right triangle?

Mathematics

2 answers:

Y_Kistochka [10]4 years ago

5 0

Answer:

Yes, is a right triangle

Step-by-step explanation:

To know if you can build a right triangle with those sides we have to make the following equality

h² = l1² + l2²

The hypotenuse is always the longest side so it should be 15

we check the equality of the equation

15² = 9² + 12²

225 = 81 + 144

225 = 225

Equality was fulfilled so it is a right triangle

IrinaVladis [17]4 years ago

4 0

Answer:

Yes.

Step-by-step explanation:

Use the Pythagorean thereom to check. 9^2+12^2=15^2

225=225

So yes.

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Question on picture. Please help

Elden [556K]

A rhombus is quadrilateral where all 4 sides are of equal length. Thus

5x + 2 = 2x + 12

3x = 10

x = 10/3

substituting x into either expression, yields

56/3

therefore side AB = 56/3

3 0

4 years ago

Simplify using PEMDAS <br>2x - 3X + 4X -5X=

adoni [48]

Answer:

3x+4x=7x

2x_(_5x)

2x+5x=7x

7x+7x=14x

x=14÷2=7

4 0

3 years ago

A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con

marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

$P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)$

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

$P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}$

$=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}$

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

$=P(r$

$=P(r=0)+P(r=1)+P(r=2)+P(r=3)$

$=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}$

$=0.017951+0.072527+0.146154+0.195856$

$=0.432488$

(iii) The expected number of people who would not see a doctor

$=np$

$=300\times 0.01$

7 0

3 years ago

Three out of evry 45 tickets sold in a food bank raffle will win a prize.If Eli bought 15 tickets, how many prizes would he expe

evablogger [386]

i would say you need to divide 45 and 3. then subtract 45 and 15. then with those two numbers you need to put the amount from 45 / 3 on the top and the 15-45 on the bottom. you will get the probability.

i think don't quote me

7 0

4 years ago

If a necklace was marked up to 400% and was originally $100 what was the original price

Dafna1 [17]

Well if the number is 100 dollars and it increases by four hundred percent it now costs 400 dollars. But if it was 100 dollars after the increase the original price was 25 dollars.

3 0

4 years ago