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Elanso [62]
3 years ago
5

Erik and Nita are playing a numers game. If the difference of their two numbers is less than 10 then Erik wins. If the differece

between their two numbers is greater than 10 then Nita wins. The numbers to choose from are zero to twenty. What is the range of numbers that will win the game for your player? (Erik) If your player is Erik, assume that Nita chooses 7. Remember that Erik and Nita can only use numbers from zero to twenty)
Mathematics
1 answer:
Over [174]3 years ago
3 0

Answer:

The range of numbers that will win the game for your player is 0 \leq x \leq 16.

Step-by-step explanation:

We are given that Erik and Nita are playing a numbers game. If the difference between their two numbers is less than 10 then Erik wins. If the difference between their two numbers is greater than 10 then Nita wins.

The numbers to choose from are zero to twenty.

Our player's name is Erik and we have to find the range of numbers that will win the game for Erik.

Given that Nita chooses 7.

Since we know that if the difference between the numbers chosen by Erik and Nita is less than 10 then Erik wins, so the inequality represented taking into account that Nita chooses 7 is given by;

|x-7| ,  where x = number chosen by Erik, i.e. 0 \leq x\leq 20

Further solving the above equation we get;

-10 < x-7

-10+7 < x-7+7 < 10 + 7

-3 < x < 17

But keeping in mind the fact that Erik and Nita can choose numbers between 0 and 20 (inclusive) only.

SO, the required range of numbers that can win Erik the game is given by = 0 \leq x \leq 16.

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Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

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Step-by-step explanation:

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4 years ago
Previously, an organization reported that teenagers spent an average of 4.3 hours per week, on average, on the phone. The organi
yKpoI14uk [10]

Answer:

The null hypothesis is H_{0} = 4.3.

The alternate hypothesis is H_{a} > 4.3

Step-by-step explanation:

Null hypothesis:

The previously report, the known value.

Alternate hypothesis:

What is questioned(higher, lower, different,...) of the null hypothesis

Previously, an organization reported that teenagers spent an average of 4.3 hours per week, on average, on the phone.

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That is, higher than 4.3. So

The alternate hypothesis is H_{a} > 4.3

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