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kolezko [41]
3 years ago
5

Shawn bought fruit last week, consisting of 2.26 pounds of bananas, ​ 1.5 pounds of grapes, and a watermelon that weighed 6.78 p

ounds. ​ ​ ​What is the total weight, in pounds, of the fruit that Shawn bought last ​week?
Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

10.54 pounds is right answer

Step-by-step explanation:

bananas 2.26  pounds

Grapes  1.5 pounds

water melon 6.78 pounds

total weight = 10.54 pounds

tiny-mole [99]3 years ago
4 0

Answer:

10.54 pounds

Step-by-step explanation:

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amid [387]
2t + 5b = 20
8t + 3b = 29
Multiply the first equation by-4
-8t -20b = -80
8t + 3b = 29
-17b = -51
b = 3
Plug 3 in for b into either equation and solve for t.
2t + 5(3) = 20
2t + 15 = 20
2t = 5
Divide both sides by 2
t = 2.50
5 0
3 years ago
Can someone answer fast.plsss
Anika [276]

Answer:

a

Step-by-step explanation:

sec (thita) = squrt (5)

squaring on both sides:

sec^2 (thita) = 5 - equation 1

1 + tan^2 (thita) = 5

tan^2 (thita) = 4

tan (thita) = 2.

= tan (thita) - squrt(5)sin(thita)

= 2 - squrt(5) x 2/ squrt(5)

= 0

from eqn - 1

sec(thita) = squrt(5)

cos(thita) = 1/ squrt(5)

sin(thita) = squrt ( 1- 1/(squrt (5))^2)

sin(thita) = 2/ squrt(5) .

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3 years ago
if the number 517*324 is completely divisible by 3, then what is the smallest whole number that could replace the *?​
Lelechka [254]

Answer:

2

Step-by-step explanation:

5+1+7+x+3+2+4=x+22

x+22 is divisible by 3,

multiple of 3 are 3,6,9,12,15,18,21,24,27,...

if x=2 ,then x+22=2+22=24

so smallest number is 2

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Surface area of a cylinder with binomials
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Find the fifth roots of 243(cos 260° + i sin 260°).
Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5)  where k=0,1,2,3,4


So the first root of 243 (cos 260° + i sin 260°)  

is z1 =  243^1/5 ( cis ( 260 + 360 *0)/5)  

          3 cis ( 260/5)

        = 3 cis (52)

        = 3 cos (52 + i sin 52)


The second root of  243 (cos 260° + i sin 260°)  

is z2 =  243^1/5 ( cis ( 260 + 360 *1)/5)  

          3 cis ( 620/5)

        = 3 cis (124)

        = 3 cos (124 + i sin 124)


The third root of  243 (cos 260° + i sin 260°)  

is z3 =  243^1/5 ( cis ( 260 + 360 *2)/5)  

          3 cis ( 980/5)

        = 3 cis (196)

        = 3 cos (196 + i sin 196)


The fourth root of  243 (cos 260° + i sin 260°)  

is z4 =  243^1/5 ( cis ( 260 + 360 *3)/5)  

          3 cis ( 1340/5)

        = 3 cis (268)

        = 3 cos (268 + i sin 268)


The fifth root of  243 (cos 260° + i sin 260°)  

is z5 =  243^1/5 ( cis ( 260 + 360 *4)/5)  

          3 cis ( 1700/5)

        = 3 cis (340)

        = 3 cos (340 + i sin 340)

6 0
3 years ago
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