Answer:
The equation for the amount of dollars pledged in total is f(M) = 2.00M + 7.25, and the amount for just Kiara is f(M) = 0.25M + 5.25
Step-by-step explanation:
The amount they pledge up front is a constant and therefore need to be added to the end of the equation. The amount per mile should be a variable amount. This gets multiplied by the M variable. So we start with the Kiara amount.
0.25 per mile = 0.25M
5.25 pledged = 5.25
Now put them together to get f(M) = 0.25M + 5.25
Do the same with Mark.
1.75 per mile = 1.75M
2.00 pledged = 2.00
Now put them together to get f(M) = 1.75M + 2.00
To get the final total, we add both equations together.
f(M) = 0.25M + 5.25 + 1.75M + 2.00
f(M) = 2.00M + 7.25
Answer:
C) x = 9
Step-by-step explanation:
When two segments intersect in a circle like so, the product of the two parts of one segment will be equal to the product of the two parts of the other segment.
So,<em> 3 * 6 = x * 2</em>
Multiply: 18 = x * 2
Divide: x = 9
<h3>
Answer: 270.58 dollars</h3>
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Work Shown:
- A = account value after t years
- P = principal or amount deposited = 800
- r = interest rate in decimal form = 0.06
- n = number of times we compound per year = 1
- t = number of years = 5
So,
A = P*(1+r/n)^(n*t)
A = 800*(1+0.06/1)^(1*5)
A = 1070.58046208
A = 1070.58
After five years, the account will have $1,070.58 in it.
The amount of interest earned is A-P = 1070.58 - 800 = 270.58 dollars.
Answer:
5, -12, -3
Step-by-step explanation:
A constant is a number by itself. Here, you can see that 5X is paired with a letter, that means that 5X is not a constant. So you could say that any whole number is a constant number and in this problem, 5, -12 and -3 are all the constant numbers in this expression.
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is
where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A
We do the same for company C
This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A
